answer : False
The measure of a tangent-tangent angle is one - half the difference of the measures of the intercepted arcs.
The diagram is attached below
AB and BC are the two tangents
By exterior angle theorem
∠3 = ∠2 + ∠4
So ∠2 = ∠3 - ∠4
Now we find angle 3 and 4, we know when a chord and tangent intersect at a point then the measure of angle is one half of measure of intercepted arc
∠3 = 
∠4 = 
∠2 = ∠3 - ∠4
∠2 = -
∠2 = 
The measure of a tangent-tangent angle is one half the difference of the measures of the intercepted arcs.
I think eight because if you add those days together they will play again in eight days so that they play on the same day.
Sorry if I got it wrong I tried and that's what counts, right?
<h2>
Greetings!</h2>
Answer:
x = −4 and x = 4
Step-by-step explanation:
4x² = 64
Lets get x² on its own. To do this we divide each sides by 4:
x² = 16
Now to get just x, we need to square root this answer:
√x² = √16
x = √16
x = 4
But this can be ±4 as it -4 and 4 squared both give 16.
So your answer is x = −4 and x = 4
<h2>Hope this helps!</h2>
Answer: pretty sure 506, 508, 510
Step-by-step explanation:
