So we are given the mean and the s.d.. The mean is 100 and the sd is 15 and we are trying the select a random person who has an I.Q. of over 126. So our first step is to use our z-score equation:
z = x - mean/s.d.
where x is our I.Q. we are looking for
So we plug in our numbers and we get:
126-100/15 = 1.73333
Next we look at our z-score table for our P-value and I got 0.9582
Since we are looking for a person who has an I.Q. higher than 126, we do 1 - P. So we get
1 - 0.9582 = 0.0418
Since they are asking for the probability, we multiply our P-value by 100, and we get
0.0418 * 100 = 4.18%
And our answer is
4.18% that a randomly selected person has an I.Q. above 126
Hopes this helps!
X + 5 , y + 2 when you are translating and if you are going up or right it’s going to be positive and it’s going to be negative if you’re going down or left
Answer:
q = 177/13
Step-by-step explanation:
3q - 16q = 7 + 2(-89 – 3)
-13q = 7 + 2(-92)
-13q = 7 - 184
-13q = -177
q = (-177)/(-13)
q = 177/13
Equation is y=kx. We have four chance to figure out k; hopefully they all give the same result
x=9, y=63, y=kx becomes 63=k(9) so k=63/9=7
x=4, y=28, 28=k(4), k=7
The constant of proportionality is 7; we check 2×7=14, 11×7=77
Answer: k=7, y=7x
