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liberstina [14]
3 years ago
9

Can someone help me out thanks!!

Mathematics
2 answers:
vichka [17]3 years ago
6 0

Answer:

x = 8

Step-by-step explanation:

16/x = x/4

x²= 16 × 4

x² = 64

x = √64

x = 8

Hope this helps.

jekas [21]3 years ago
3 0
X=8.

Hope this helps
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One positive number is one-fifth of another number. The difference between the two numbers is 144, find the numbers.
liubo4ka [24]

Answer:

36, 180

Step-by-step explanation:

x = y/5, so y = 5x

y - x = 144

5x - x = 144

4x = 144

x = 144/4 = 36

y = 5x = 5*36 = 180

The two numbers are 36 and 180

7 0
2 years ago
• karger's min cut algorithm in the class has probability at least 2/n2 of returning a min-cut. how many times do you have to re
MrRissso [65]
The Karger's algorithm relates to graph theory where G=(V,E)  is an undirected graph with |E| edges and |V| vertices.  The objective is to find the minimum number of cuts in edges in order to separate G into two disjoint graphs.  The algorithm is randomized and will, in some cases, give the minimum number of cuts.  The more number of trials, the higher probability that the minimum number of cuts will be obtained.

The Karger's algorithm will succeed in finding the minimum cut if every edge contraction does not involve any of the edge set C of the minimum cut.

The probability of success, i.e. obtaining the minimum cut, can be shown to be ≥ 2/(n(n-1))=1/C(n,2),  which roughly equals 2/n^2 given in the question.Given: EACH randomized trial using the Karger's algorithm has a success rate of P(success,1) ≥ 2/n^2.

This means that the probability of failure is P(F,1) ≤ (1-2/n^2) for each single trial.

We need to estimate the number of trials, t, such that the probability that all t trials fail is less than 1/n.

Using the multiplication rule in probability theory, this can be expressed as
P(F,t)= (1-2/n^2)^t < 1/n 

We will use a tool derived from calculus that 
Lim (1-1/x)^x as x->infinity = 1/e, and
(1-1/x)^x < 1/e   for x finite.  

Setting t=(1/2)n^2 trials, we have
P(F,n^2) = (1-2/n^2)^((1/2)n^2) < 1/e

Finally, if we set t=(1/2)n^2*log(n), [log(n) is log_e(n)]

P(F,(1/2)n^2*log(n))
= (P(F,(1/2)n^2))^log(n) 
< (1/e)^log(n)
= 1/(e^log(n))
= 1/n

Therefore, the minimum number of trials, t, such that P(F,t)< 1/n is t=(1/2)(n^2)*log(n)    [note: log(n) is natural log]
4 0
3 years ago
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Stolb23 [73]
Answer is C                                                              qwertyuiopoiuytrewertyuioiuytrewerty
8 0
3 years ago
The sum of the differences must be zero for any distribution consisting of n observations.
Semenov [28]

Answer:

false

Step-by-step explanation:

7 0
3 years ago
a car can travel 19.6 miles for every 1 gallon of gasoline. calculate the number of miles the car can travel on 13.8 gallons of
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I believe it 270.48 miles. 
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