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Gemiola [76]
3 years ago
10

At sunset, the temperature was 4 degrees. Then at sunrise the next morning, it was -7 degrees. What is the difference between th

ese temperatures?
Mathematics
1 answer:
maw [93]3 years ago
6 0
It's 11 degrees.

Since you have to do 4 - -7, you can leave the seven, change the subtraction sign to an addition, and make -7 the opposite (7), the equation would be 4 + 7, making it 11 degrees.
You might be interested in
Where should the point P be chosen on line segment AB so as to maximize the angle θ? (Assume a = 4 units, b = 5 units, and c = 9
taurus [48]
From the figure, let the distance of point P from point A on line segment AB be x and let the angle opposite side a be M and the angle opposite side c be N.

Using pythagoras theorem,
\tan M= \frac{a}{b-x} \\ \\ M=\tan^{-1}\left(\frac{a}{b-x}\right)
and
\tan N= \frac{c}{x} \\ \\ N=\tan^{-1}\left(\frac{c}{x}\right)

Angle θ is given by
\theta=180-M-N \\  \\ =180-\tan^{-1}\left(\frac{a}{b-x}\right)-\tan^{-1}\left(\frac{c}{x}\right)

Given that a = 4 units, b = 5 units, and c = 9 units, thus
\theta=180-\tan^{-1}\left(\frac{4}{5-x}\right)-\tan^{-1}\left(\frac{9}{x}\right)

To maximixe angle θ, the differentiation of <span>θ with respect to x must be equal to zero.
i.e.
\frac{d\theta}{dx} = -\frac{4}{x^2-10x+41} + \frac{9}{x^2+81} =0 \\  \\ -4(x^2+81)+9(x^2-10x+41)=0 \\  \\ -4x^2-324+9x^2-90x+369=0 \\  \\ 5x^2-90x+45=0 \\  \\ x^2-18x+9=0 \\  \\ x=9\pm6 \sqrt{2}

Given that x is a point on line segment AB, this means that x is a positive number less than 5.

Thus
x=9-6 \sqrt{2}=0.5147

Therefore, The distance from A of point P, so that </span>angle θ is maximum is 0.51 to two decimal places.
6 0
3 years ago
Please help I need to get this done
satela [25.4K]

Answer:

Your answer is drawn in the picture.

Step-by-step explanation:

Solve for <Q and then figure out which degree is bigger which mean that degree's side is big.

3 0
2 years ago
Use the image to match the arc/angle measure.
IrinaK [193]

Answer:

The following measurements are:

m\angle{STR}=23^\circ (Option #4)

m{QT}=142^\circ (Option #7)

mST=134^\circ (Option #5)

mRQ=38^\circ (Option #2)

Step-by-step explanation:

To begin, we can find the measure of \angle{STR} by applying the inscribed angle theorem: an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

Since the intercepted arc (RS) is 46 degrees, we have:

46=2\theta\\23=\theta

Next, we can find the measure of arc QT using the same theorem. So,

QT=2(71)\\QT=142

Notice that the chord RT is actually a diameter. From the theorem about the inscribed angle including a diameter, we know that the intercepted arc will have a measure of 180^\circ. Since the arc ST is part of the arc RST, and we know RS is 46^\circ, we can set up and solve this equation:

RST = RS + ST\\180 = 46 + ST\\134 = ST

We can use the same idea to find RQ. We know that RQT is 180^\circ and QT is 142^\circ, so:

RQT = RQ + QT\\180 = RQ + 142\\38 = RQ

7 0
2 years ago
Rewrite the expression with the given base.
satela [25.4K]
C. 8^4x
64^2x = 4096x
8^4x= 4096x
3 0
3 years ago
Read 2 more answers
at its highest point, the elevation of a city is 5791 ft above sea level. At its lowest point, the elevation of another city is
Nat2105 [25]
5785 feet between the top and sea level hope this helps 
8 0
3 years ago
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