We have an exponential with a fractional base and a positive exponent, and a positive sign at front. Each time we multiply a fraction between zero and one by itself it gets smaller. So as x increases we'll go to zero. As x decreases it goes to positive infinity, as negative powers are the reciprocals of positive power.
The left end approaches positive infinity and the right end approaches zero.
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X^2-4x-32=0
(x+a)(x+b)
x^2-(a+b)x+ab
a+b=4
ab=-32
a=-b+4
(-b+4)b=-32
-b^2+4b=-32
b^2-4b-32=0
b=8,-4
If b=8, a=-4
If b=-4, a= 8
Plug in a and b to (x+a)(x+b)
x= -4, 8
Answer:
Translated below: Answer is B.
Step-by-step explanation:
1. Set number to 5.
2. Check if it is less than 0.
3. It is not. Nothing is printed.
4. Change number to -5.
5. Check if it is less than 0. It is.
6. Print the number.
The output will just be -5.
B.
