All categories

2 years ago

What is the equation of a line that is parallel to 2x+3y=3 and passes through the point (3, −4) ?

Mathematics

1 answer:

svetlana [45]2 years ago

8 0

.................................

You might be interested in

Which of the following functions best describes this graph? HELP A BROTHA OUT

koban [17]

I got chu babe it’s A

5 0

3 years ago

Read 2 more answers

Write the inverse function for the function, ƒ(x) = x + 4. Then, find the value of ƒ -1(4). Type your answers in the box.

KATRIN_1 [288]

F(x)^-1=x-4
f(4)^-1=0

8 0

3 years ago

2. Randy has a house that is worth $250,000 but he still owes $175,000. He has a car that is worth $50,000 but he still owes $37

faust18 [17]

Answer:

$91,200

Step-by-step explanation:

I gave it my best shot sorry if it wrong

3 0

2 years ago

If (x+5) is a factor of 3x^2+14x+k, what is the value of k?

kherson [118]

If (x+5) is a factor the equation will equal zero when x=-5 so

3(-5^2)+14(-5)+k=0

75-70+k=0

5+k=0

k=-5

7 0

3 years ago

An apartment complex rents an average of 2.3 new units per week. If the number of apartment rented each week Poisson distributed

masya89 [10]

Answer:

$P(X\leq 1) = 0.331$

Step-by-step explanation:

Given

Poisson Distribution;

Average rent in a week = 2.3

Required

Determine the probability of renting no more than 1 apartment

A Poisson distribution is given as;

$P(X = x) = \frac{y^xe^{-y}}{x!}$

Where y represents λ (average)

y = 2.3

Probability of renting no more than 1 apartment = Probability of renting no apartment + Probability of renting 1 apartment

Using probability notations;

$P(X\leq 1) = P(X=0) + P(X =1)$

Solving for P(X = 0) [substitute 0 for x and 2.3 for y]

$P(X = 0) = \frac{2.3^0 * e^{-2.3}}{0!}$

$P(X = 0) = \frac{1 * e^{-2.3}}{1}$

$P(X = 0) = e^{-2.3}$

$P(X = 0) = 0.10025884372$

Solving for P(X = 1) [substitute 1 for x and 2.3 for y]

$P(X = 1) = \frac{2.3^1 * e^{-2.3}}{1!}$

$P(X = 1) = \frac{2.3 * e^{-2.3}}{1}$

$P(X = 1) =2.3 * e^{-2.3}$

$P(X = 1) = 2.3 * 0.10025884372$

$P(X = 1) = 0.23059534055$

$P(X\leq 1) = P(X=0) + P(X =1)$

$P(X\leq 1) = 0.10025884372 + 0.23059534055$

$P(X\leq 1) = 0.33085418427$

$P(X\leq 1) = 0.331$

Hence, the required probability is 0.331

6 0

2 years ago