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drek231 [11]
3 years ago
10

Please help. I’ll give brainliest

Mathematics
2 answers:
iren2701 [21]3 years ago
7 0

Answer:

4/15

Step-by-step explanation:

Multiples of 4: 4, 8, 12, 16, 20, 24, 28 (there are 7)

19: There is 1

Total: 7+1=8

8/30=4/15

Pavel [41]3 years ago
3 0
The correct answer is 4/15
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The diameter of a circle has endpoints P(-12, -4) and Q(6, 12).
nexus9112 [7]

9514 1404 393

Answer:

  (x +3)² +(y -4)² = 145

Step-by-step explanation:

The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...

  A = (P +Q)/2

  A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2

  A = (-3, 4)

The equation of the circle for some radius r is ...

  (x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle

The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...

  (6 +3)² +(12 -4)² = r² = 9² +8²

  r² = 81 +64 = 145

Then the equation of the circle is ...

  (x +3)² +(y -4)² = 145

3 0
3 years ago
Suppose that 80% of all trucks undergoing a brake inspection at a certain inspection facility pass the inspection. Consider grou
Gwar [14]

Answer:

P=0.147

Step-by-step explanation:

As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2

We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.

We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) .  To find the required probability 3 mentioned probabilitie have to be summarized.

So P(9/16 )=  C16 9 * P(good brakes)^9*Q(bad brakes)^7

P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02

P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007

P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12

P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147

7 0
3 years ago
.............helppppppppppppppppppp
raketka [301]

Answer:

what????????????????

8 0
3 years ago
Read 2 more answers
I really need help with this question!
ololo11 [35]
Same as all the other ones like this.

Since the two figures are similar . . .

-- The ratio of of their volumes is  R³ .

-- The ratio of their surface areas is  R² .

-- The ratio of their dimensions is  R .

So  R³  is        729 / 2744 .

Take the cube root of that and you'll have  R .

Then square R and you'll have the ratio of their surface areas.
5 0
3 years ago
Please help me with this question!!!!
beks73 [17]

Answer:

answer is A

Step-by-step explanation:

please I need brainlist

4 0
3 years ago
Read 2 more answers
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