X*y=72
x = 5y-2
x=72/y
72/y=5y-2
72=5y^2-2y
5y^2 -2y - 72 = 0
(5y+18)(y-4)=0
y = -18/5 discard
or y = 4
4x=72
x=18
(18,4)
Answer:
The number of gallons of 100% mixture to be added is 6.11 gallons and the 10% mixture to be added is 48.89 gallons.
Step-by-step explanation:
Let us assume that x gallons of 10% mixture and y gallons of 100% mixture are added to make 55 gallons of 20% mixture.
So, x + y = 55 ............. (1)
And
⇒ 0.1x + y = 0.2x + 0.2y
⇒ 0.1x = 0.8y
⇒ x = 8y ........... (2)
So, from equation (1) we get, 8y + y = 55
⇒ 9y = 55
⇒ y = 6.11 gallons.
Therefore, the number of gallons of 100% mixture to be added is 6.11 gallons and a 10% mixture to be added is (55 - 6.11) = 48.89 gallons. (Answer)
Answer:
2
Step-by-step explanation:
Answer:
I'll need to know the typed options