Answer:
125/6(In(x-25)) - 5/6(In(x+5))+C
Step-by-step explanation:
∫x2/x1−20x2−125dx
Should be
∫x²/(x²−20x−125)dx
First of all let's factorize the denominator.
x²−20x−125= x²+5x-25x-125
x²−20x−125= x(x+5) -25(x+5)
x²−20x−125= (x-25)(x+5)
∫x²/(x²−20x−125)dx= ∫x²/((x-25)(x+5))dx
x²/(x²−20x−125) =x²/((x-25)(x+5))
x²/((x-25)(x+5))= a/(x-25) +b/(x+5)
x²/= a(x+5) + b(x-25)
Let x=25
625 = a30
a= 625/30
a= 125/6
Let x= -5
25 = -30b
b= 25/-30
b= -5/6
x²/((x-25)(x+5))= 125/6(x-25) -5/6(x+5)
∫x²/(x²−20x−125)dx
=∫125/6(x-25) -∫5/6(x+5) Dx
= 125/6(In(x-25)) - 5/6(In(x+5))+C
Answer:
in 84 minutes or 1 hr, 24 min
Step-by-step explanation:
you need to find the least common multiple of 2, 3 and 28 which is 84
Answer:
see below
Step-by-step explanation:
h(t)=−4.9t2+100t+325.
The independent variable is the one that we change
t which is in seconds
The dependent variable is the result
h(t) which is in meters
Answer: it’s 65 degrees
Step-by-step explanation: The angles 6 and 3 are alternate interior angles (basically their the same measure) so both will be 65 degrees!
Answer:
idk aljebra 2 either and i just got the same question how?
Step-by-step explanation:
