All categories

4 years ago

A system of equations is shown below:

1 answer:

4 0

The answer is (3,-1). You can also plug it back into the equation to check.

You might be interested in

grandymaker [24]

A) around 13 ish. It's hard to frel the exact point. B) 26.08 C) .77 I hope that this helps

4 0

3 years ago

Vinil7 [7]

Note: The third term of the sequence should be $\dfrac{27}{2}$ instead of $\dfrac{37}{2}$ , otherwise the sequence has no common ratio.

Given:

The given sequence is

$24,18,\dfrac{27}{2},\dfrac{81}{8}$

To find:

The common ratio of the given sequence.

Solution:

The quotient of each pair of consecutive terms are:

$\dfrac{18}{24}=\dfrac{3}{4}$

Similarly,

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{27}{36}$

$\dfrac{\dfrac{27}{2}}{18}=\dfrac{3}{4}$

And,

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{81}{8}\times \dfrac{2}{27}$

$\dfrac{\dfrac{81}{8}}{\dfrac{27}{2}}=\dfrac{3}{4}$

Therefore, the common ratio of the given sequence is $\dfrac{3}{4}$ or 0.75.

8 0

3 years ago

Vera_Pavlovna [14]

Convert the mixed number 2 1/4 into an improper fraction: 9/4.

Then multiply this 9/4 by 3: 27/4, or 6 3/4.

5 0

3 years ago

Alborosie

Equations don't have minimum or maximum, functions do.

Function y=2n^2+5n-25 has minimum -28.125, has no maximum.

8 0

3 years ago

Luba_88 [7]

30 I believe, sorry if I am wrong, I am bad at math and history.

8 0

3 years ago