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Keith_Richards [23]
3 years ago
9

Please Help ASAP Select the true statement regarding the end behavior of the functions.

Mathematics
2 answers:
bagirrra123 [75]3 years ago
8 0

I think the answer is D.

nataly862011 [7]3 years ago
6 0

Answer:

Option A. is the answer.

Step-by-step explanation:

In the given table for f(x), we see that for every value of x, function f(x) is decreasing.

f(-2) = 48

f(0) = 12

f(2) = 3

f(3) = 1.5

In other words as the value of x increases, f(x) is approaching towards 0.

Now we take another function g(x) = 2^{x}-5

Now we plug in the values of x to get the values of g(x)

g(-1) =  2^{-1}-5

      = \frac{1-10}{2}

      = -\frac{9}{2} = -4.5

g(0) =  2^{0}-5

      = 1 - 5 = -4

g(2) = 2^{2}-5

     = 4 - 5 = -1

g(3) = 2^{3}-5

      = 8 - 5

     = 3

Now we find that g(x) is increasing with the values of x.

Now we take third function h(x). By analyzing the given graph we find

h(-4) = 2

h(0) = 3

h(1) = 5

So when we are increasing the value of x function h(x) is increasing.

Finally we conclude by the options given that f(x) is the only function which tends to 0 with the increase in the values of x.

Option A. is the answer.

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Find the domain for the particular solution to the differential equation dy dx equals the quotient of 3 times y and x , with ini
Svetach [21]
For this case we have the following difference equation:
 dy / dx = 3xy

 Applying separable variables we have:
 dy / y = 3xdx

 Integrating both sides we have:
 \int\ ({1/y}) \, dy =  \int\ {3x} \, dx
 ln (y) = (3/2) x ^ 2 + C

 applying exponential to both sides:
 exp (ln (y)) = exp ((3/2) x ^ 2 + C)

 y = C * exp ((3/2) x ^ 2)
 For y (1) = 1 we have:
 C = 1 / (exp ((3/2) * 1 ^ 2))

C = 0.2
 Thus, the particular solution is:
 y = 0.2 * exp ((3/2) x ^ 2)

 Whose domain is all real.
 Answer:
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 Domain: all real numbers
6 0
3 years ago
Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively. How many times will t
Evgen [1.6K]

Answer:

60 times will they ring together at the same second in one hour excluding the one at the end.

Step-by-step explanation:

Given : Five bells begin to ring together and they ring at intervals of 3, 6, 10, 12 and 15 seconds, respectively.

To find : How many times will they ring together at the same second in one hour excluding the one at the end?

Solution :

First we find the LCM of 3, 6, 10, 12 and 15.

2 | 3  6  10  12  15

2 | 3  3   5   6  15

3 | 3  3   5   3  15

5 | 1    1  5   1    5

  | 1    1   1   1     1

LCM(3, 6, 10, 12,15)=2\times 2\times 3\times 5

LCM(3, 6, 10, 12,15)=60

So, the bells will ring together after every 60 seconds i.e. 1 minutes.

i.e. in 1 minute they rand together 1 time.

We know, 1 hour = 60 minutes

So, in 60 minute they rang together 60 times.

Therefore, 60 times will they ring together at the same second in one hour excluding the one at the end.

6 0
3 years ago
What's equivalent to 2x+3x+8-3x-2? Options arte 2x+6, 2x+10, 5x-3x+6, 5x-3x+10 Select all that are equivalent.
victus00 [196]
2x+6 I believe is the answer
8 0
3 years ago
Read 2 more answers
This is for math, this is a test great help
RUDIKE [14]

Answer:

12.5

Step-by-step explanation:

8 0
3 years ago
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mr. larsen's third grade class has 22 students, 12 girls and 10 boys. two students must be selected at random to be in the fall
faust18 [17]

The probability that no boys will be chosen is 0.2857

What is probability?

The area of arithmetic called likelihood deals with numerical representations of the chance that an incident can occur or that a press release is true.

Main Body:

Total students =22

total boys = 10

total girls =12

Now we have to chose 2 girls from 12 , so combination is used to select ,

⇒¹²C₂

Also, We have to chose 2 girls from 22 students

so it can be represented as ,

⇒²²C₂

Probability of choosing 2 girls = ¹²C₂/²²C₂

On solving this we will get = 0.2857

Hence the probability is 0.2857

To know more about probability , visit;

brainly.com/question/13604758

#SPJ4

5 0
1 year ago
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