Answer:
I cant im bleeding to death and opijhi whoops i cant feeo my fengrs
Step-by-step explanation:
Question A is b and question B is d
y = - \frac{2}{5} x - 2
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
rearrange 2x + 5y = 10 into this form
subtract 2x from both sides
5y = - 2x + 10 ( divide all terms by 5 )
y = - \frac{2}{5} x + 2 ← point- slope form with slope m = - \frac{2}{5}
Parallel lines have equal slopes hence
y = - \frac{2}{5} x + c is the partial equation of the parallel line
to find c, substitute ( 5, - 4 ) into the partial equation
- 4 = - 2 + c ⇒ c = - 4 + 2 = - 2
y = - \frac{2}{5} x - 2 ← equation of parallel line
<u>The question does not clearly specify from which endpoint Q is at 2/3. I'll assume Q is 2/3 away from R.</u>
Answer:
<em>The point Q is (2,3)</em>
Step-by-step explanation:
Take the aligned points R(-2,1), S(4,4), and Q(x,y) in such a way that Q is 2/3 away from R (assumed).
The required point Q must satisfy the relation:
d(RQ) = 2/3 d(RS)
Where d is the distance between two points.
The horizontal and vertical axes also satisfy the same relation:
x(RQ) = 2/3 x(RS)
And, similarly:
Working on the first condition:
Removing the parentheses:
Adding 2:
x = 2
Similarly, working with the vertical component:
Removing the parentheses:
Subtracting 1:
y = 3
The point Q is (2,3)
Answer:
Use SAS to show that triangles PRQ and PRS are congruent.
Step-by-step explanation:
Since PR bisects angle QPS, angles QPR and SPR are congruent. By reflexive property of congruence, PR is congruent to itself. Since PQ is congruent to PS, we can use SAS to show that the two triangles are congruent. By CPCTC, QR is congruent to SR.
