Question

What are the roots of the equation x2 – 14x + 74 = 0 in simplest a + bi form?

Answer 1

$\huge\text{Hey there!}$

$\large\text{Use these formulas to solve for this equation.}\\\\\\\mathsf{ax^2 + bx + c = 0}\\\\\\\mathsf{x = \dfrac{-b \pm\sqrt{b^2-4ac}}{2a}}$

$\mathsf{x^2-14x + 74= 0}$

$\mathsf{1x^2 + (-14x) + 74= 0}$

$\large\text{Whereas, a = 1, b = -14, \& c = 74}$

$\mathsf{x =\dfrac{-(-14)\pm \sqrt{(-14)^2 - 4(1)(74)}}{2(1)}}$

$\mathsf{-(-14) = \bf 14}\\\\\mathsf{(-14)^2-4(1)(74)=\bf -100}$

$\mathsf{x = \dfrac{14\pm \sqrt{-100}}{2}}$

$\boxed{\boxed{\large\textsf{Answer: \huge \bf No real solutions}}}\huge\checkmark$

$\large\text{Good luck on your assignment and enjoy your day!}$

~$\frak{Amphitrite1040:)}$