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3 years ago

What are the solutions of the quadratic equation 49x^2=9?

1 answer:

5 0

<span>Simplifying 49x^2 + -9 = 0
Reorder the terms: -9 + 49x^2 = 0
Solving -9 + 49x^2 = 0 Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '9' to each side of the equation. -9 + 9 + 49x^2 = 0 + 9
Combine like terms: -9 + 9 = 0 0 + 49x^2 = 0 + 9 49x^2 = 0 + 9
Combine like terms: 0 + 9 = 9 49x^2 = 9
Divide each side by '49'. x^2 = 0.1836734694
Simplifying x^2 = 0.1836734694
Take the square root of each side: x = {-0.428571429, 0.428571429}

hope this helps!!</span>

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At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic

finlep [7]

Answer:

a) We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) $P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) $P(C=0) = 0.05$

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C 0 1 2 3 4 5 6 7 8

P 0.05 0.14 0.34 0.24 0.11 0.07 0.02 0.02 0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) $\sum_{i=1}^n P_i = 1$

$0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1$

2) $P_i \geq 0 , \forall i=1,2,...,n$

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

$P(C \geq 1)$

And we can use the complement rule and we got:

$P(C \geq 1)= 1-P(C$

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

$P(C=0) = 0.05$

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

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3 years ago

Find X in the figure below.

Hitman42 [59]

<h3>Answer:</h3>

x = 3

<h3>Explanation:</h3>

The product of the lengths of segments from the intersection point to the circle is the same for both secants.

... 1×6 = 2×x

... 6/2 = x = 3 . . . . . divide by 2

_____

<em>Comment on secant geometry</em>

Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.

When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.

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3 years ago

Find the least common denominator between the two fractions. and 2 12 6

SSSSS [86.1K]

The least common denominator is 2

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3 years ago

How do you put 943,261,586 with base ten numbers

Citrus2011 [14]

Answer:

(9 $\times$ $10^{8}$ ) + (4 $\times$ $10^{7}$ ) + (3 $\times$ $10^{6}$ ) + (2 $\times$ $10^{5}$ ) + (6 $\times$ $10^{4}$ ) + ( $10^{3}$ ) + (5 $\times$ $10^{2}$ ) + (8 $\times$ 10) + (6 $\times$ $10^{0}$ )

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586 =

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

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3 years ago

50 points

NISA [10]

1. Using your straightedge, draw a reference line, if one is not provided.
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3. Construct a perpendicular at point B' to the line through ab2.
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5. With your compass still set at a span representing AB, place the compass point at C and swing an arc to the left.
6. Holding this same span, place the compass point at A' and swing an arc intersecting with the previous arc. Label the point of intersection as D.
7. Connect points A' to D, D to C, and C to B' to form a square.

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3 years ago