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alex41 [277]
3 years ago
14

please please please please please please please please please please please please please solve this ​

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0

Answer:

a

Step-by-step explanation:

NISA [10]3 years ago
6 0

Answer:

I hope that the picture attached will give you the right answer

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What is the value of the x-coordinate of point A?
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Answer:

X Coordinate. The horizontal value in a pair of coordinates: how far along the point is. The X Coordinate is always written first in an ordered pair of coordinates (x,y), such as (12,5). In this example, the value "12" is the X Coordinate.

I hope I can help you :)

4 0
3 years ago
How much do you make annually at 15 dollars an hour 23 hours a week?
ahrayia [7]
You multiply $15 by 23 which is 345. Then you multiply 345 by 52 for there is 52 in a year. The answer $17940.
4 0
3 years ago
Read 2 more answers
What are the solutions of the quadratic equation 4x2 - 8x – 12 = 0?
Juliette [100K]

Answer:

see bottom

Step-by-step explanation:

divide through by 4

x2 - 2x - 3 = 0

x2 - 3x + x - 3 = 0

(x2 - 3x) + (x - 3) = 0

x(x - 3) + 1(x - 3) = 0

(x + 1) (x - 3) = 0

x + 1 = 0 and x - 3 = 0

x = -1 and x = 3

5 0
3 years ago
Show your work if you can :)
meriva
I believe it’s just 61/100
5 0
3 years ago
The half life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
Veronika [31]

Using an exponential function, it is found that:

a) N(t) = 75(0.5)^{\frac{t}{3.8}}

b) 37.5 grams of the gas remains after 3.8 days.

c) The amount remaining will be of 10 grams after approximately 11 days.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

  • A(0) is the initial value.
  • r is the decay rate, as a decimal.

Item a:

We start with 75 grams, and then work with a half-life of 3.8 days, hence the amount after t daus is given by:

N(t) = 75(0.5)^{\frac{t}{3.8}}

Item b:

This is N when t = 3.8, hence:

N(t) = 75(0.5)^{\frac{3.8}{3.8}} = 37.5

37.5 grams of the gas remains after 3.8 days.

Item c:

This is t for which N(t) = 10, hence:

N(t) = 75(0.5)^{\frac{t}{3.8}}

10 = 75(0.5)^{\frac{t}{3.8}}

(0.5)^{\frac{t}{3.8}} = \frac{10}{75}

\log{(0.5)^{\frac{t}{3.8}}} = \log{\frac{10}{75}}

\frac{t}{3.8}\log{0.5} = \log{\frac{10}{75}}

t = 3.8\frac{\log{\frac{10}{75}}}{\log{0.5}}

t \approx 11

The amount remaining will be of 10 grams after approximately 11 days.

More can be learned about exponential functions at brainly.com/question/25537936

4 0
2 years ago
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