Point H is the midpoint of side FK. Triangles F G H and K J H are connected at point H. The lengths of sides F H and H K are con
2 answers:
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This is how you add fractions..
I have solved it step-by-step. If you understand this, you'll know how to subtract, too.
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I have solved it step-by-step. If you understand this, you'll know how to subtract, too.
If you don't understand, message me :)
πAnswer:
Therefore, the area of a sector of a circle would be 13.5π square units.
Step-by-step explanation:
Given
mi
- Ф = 60°
The area of a sector of a circle is:
A = π r² Ф/360
A = π (9)² 60/360
A = π 81 * 1/6
A = 13.5π square units
Therefore, the area of a sector of a circle would be 13.5π square units.