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2 years ago

Can some please help me with this one it would be much appreciated

Mathematics

1 answer:

kherson [118]2 years ago

7 0

πAnswer:

Therefore, the area of a sector of a circle would be 13.5π square units.

Step-by-step explanation:

Given

$r=9$ mi

Ф = 60°

The area of a sector of a circle is:

A = π r² Ф/360

A = π (9)² 60/360

A = π 81 * 1/6

A = 13.5π square units

Therefore, the area of a sector of a circle would be 13.5π square units.

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2 years ago

The first term of an AP is -7 and the ratio of the eight term to the third term is 7:1 calculate the common difference

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Step-by-step explanation:

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The ratio of the eight term to third term = 7:1

$\frac{T_8}{T_3} = \frac{7}{1} = \frac{a+ 7d}{a + 2d} \\\\7 = \frac{a+ 7d}{a + 2d}\\\\Recall, a = -7\\\\7 = \frac{-7+ 7d}{-7 + 2d}\\\\7(-7 + 2d) = -7+ 7d\\\\-49 + 14d = -7 + 7d\\\\14d -7d = -7 + 49\\\\7d = 42\\\\d = \frac{42}{7} \\\\d = 6$

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