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STatiana [176]
3 years ago
11

I need the equation ​

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

Are you talking about the corrida nates

Step-by-step explanation:

Tems11 [23]3 years ago
4 0
Sorry but it could be x=2-4=y
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5. How many solutions does this system of equations have?
Diano4ka-milaya [45]

Answer:

\text{\boxed{\sf{D. \ No\  solution}}}

Step-by-step explanation:

Isolate the term of x and y from one side of the equation.

<h3>y=-4x-9 and y=-4x-1</h3>

First, you have to substitute of y=-4x-1.

\Longrightarrow: \sf{[-4x-1=-4x-9]}

<u>Add by 4x from both sides.</u>

\Longrightarrow: \sf{-4x-1+4x=-4x-9+4x}

<u>Solve.</u>

\Rightarrow:\sf{-1=-9}\\\\\Rightarrow: \sf{(-9)-(-1)=-9+1=-8}\\\\\Rightarrow: \sf{8=0}

  • <u>Therefore, the correct answer is "D. No solution".</u>

I hope this helps. Let me know if you have any questions.

8 0
2 years ago
Who wants to help I really really need it ❤️
sasho [114]
It would be 8 to the 8th power
5 0
3 years ago
Read 2 more answers
Show that ( 2xy4 + 1/ (x + y2) ) dx + ( 4x2 y3 + 2y/ (x + y2) ) dy = 0 is exact, and find the solution. Find c if y(1) = 2.
fredd [130]

\dfrac{\partial\left(2xy^4+\frac1{x+y^2}\right)}{\partial y}=8xy^3-\dfrac{2y}{(x+y^2)^2}

\dfrac{\partial\left(4x^2y^3+\frac{2y}{x+y^2}\right)}{\partial x}=8xy^3-\dfrac{2y}{(x+y^2)^2}

so the ODE is indeed exact and there is a solution of the form F(x,y)=C. We have

\dfrac{\partial F}{\partial x}=2xy^4+\dfrac1{x+y^2}\implies F(x,y)=x^2y^4+\ln(x+y^2)+f(y)

\dfrac{\partial F}{\partial y}=4x^2y^3+\dfrac{2y}{x+y^2}=4x^2y^3+\dfrac{2y}{x+y^2}+f'(y)

f'(y)=0\implies f(y)=C

\implies F(x,y)=x^2y^3+\ln(x+y^2)=C

With y(1)=2, we have

8+\ln9=C

so

\boxed{x^2y^3+\ln(x+y^2)=8+\ln9}

8 0
3 years ago
HELP ME ASAP WITH MATH MONEY &amp; WAGES
Dennis_Churaev [7]

Answer:

96,220

Step-by-step explanation:

187,400 x .3 (30%)= 56,220

56220+40000= *96,220

5 0
3 years ago
Read 2 more answers
Will give <br> BRAINLY AND FIVE STARS and A THANKS
11Alexandr11 [23.1K]

Answer:

k = 12h

Step-by-step explanation:

Since each of the inputs of h can be mutiplied by 12 to get the output k, the equation is k = 12h
Hope this helps :)

3 0
2 years ago
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