Personally I think the 3rd forth and the last one is but I’m not to sure
It is possible
Group 1 : 684 divided by 36 = 19$
Group 2 : 456 divided by 24 = 19$
Therefore, both groups 1 and 2 charge $19 for each ticket
P( 1) = 1/6
P(2) = 1/6
Probability of 1 then 2 = 1/6 * 1/6 = 1/36
