The area will be half the product of the lengths of AB and CD.
|AB| = √((6-1)² +(-2-3)²) = 5√2
|CD| = √((5-2)² +(5-2)²) = 3√2
Area = (1/2)*(5√2)*(3√2) = (1/2)*(15*2) = 15
The appropriate choice is ...
D: 15 square units
The distance between the points is 5
= 2025
When you are told to find the smallest length possible, you perform L.C.M(Least common multiples)
For this, you divide the given lengths using the numbers that divides all through.
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B) 43 because they increase 3
c) 32 because they decrease 7
It is a whole number, and is positive