Fine the x and y int of the line -10x-6y=120

I need help please and thank you

Vaselesa [24]

Answer:

Eagles

Step-by-step explanation:

2000x6=12000 this is the most

5 0

3 years ago

Read 2 more answers

Word problem plz help pt.1

shusha [124]

equation csn be represented as

money left = 500 - (n-1)×4.65

so we can see in first week money left

= 500 - (1-1)×4.65= 500-0=500

which is true because first week chaya got gift card and does not spend any money.

now lets assume that on week n money left is 327.95

so by equation

500 -(n-1)×4.65 = 327.95

500- 327.95 =( n-1)× 4.65

n -1 = 172.05/4.65=37

n = 37+1 = 38

in 38th week money left would be 327.95

3 0

3 years ago

PLS HELP I WILL MARK BRAINLIEST

tamaranim1 [39]

The green triangle is the rotated image PQR. Point of rotation is (1,-1).

The red triangle is the reflected image XYZ. It’s reflected on the x axis

3 0

3 years ago

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The length of a rectangle in centimeters is two more than thrice its width. a) Write an expression, in the simplest form, for th

Karo-lina-s [1.5K]

Answer:

Perimeter of the rectangle = 8 x +4

Length of the rectangle = 12 units.

Step-by-step explanation:

Let the width of the rectangle as 'x' units.

So, length of the rectangle is 2 more than 3 x.

We can set up expression for length as 3 x+2.

Now, perimeter is sum of all side lengths of the rectangle.

So, perimeter = x+x+3 x+2 +3 x+2

Combine like terms,

Perimeter = 8 x+4

Now, it is given perimeter is 36cm

So,

8 x+4=36

Subtract both sides 4

8 x=32

Divide both sides by 8

x=4

So, width of the rectangle =4

Length =3(4) +2=14

3 0

3 years ago

Ex 7) Imagine a mile-long bar of metal such as the rail along railroad tracks. Suppose that the rail is anchored on both ends an

Fantom [35]

9514 1404 393

Answer:

about 44.5 feet

Step-by-step explanation:

We can write relations for the height of the rail as a function of initial length and expanded length, but the solution cannot be found algebraically. A graphical solution or iterative solution is possible.

Referring to the figure in the second attachment, we can write a relation between the angle value α and the height of the circular arc as ...

h = c·tan(α) . . . . . . where c = half the initial rail length

Then the length of the expanded rail is ...

s = r(2α) = (c/sin(2α)(2α) . . . . . . where s = half the expanded rail length

Rearranging this last equation, we have ...

sin(2α)/(2α) = c/s

It is this equation that must be solved iteratively. We find the solution to be ...

α ≈ 0.0168538794049 radians

So, the height of the circular arc is ...

h = 2640.5·tan(0.0168538794049) ≈ 44.4984550191 . . . feet

The rail will bow upward by about 44.5 feet.

_____

<em>Additional comments</em>

Note that s and c in the diagram are half the lengths of the arc and the chord, respectively. The ratio of half-lengths is the same as the ratio of full lengths: c/s = 2640/2640.5 = 5280/5281.

We don't know the precise shape the arc will take, but we suspect is is not a circular arc. It seems likely to be a catenary, or something similar.

__

We used Newton's method iteration to refine the estimate of the angle from that shown on the graph. The iterator used is x' = x -f(x)/f'(x), where x' is the next guess based on the previous guess of x. Only a few iterations are required obtain an angle value to full calculator precision.

3 0

3 years ago