Answer:
The equation of line passing through point ( - 2 , 4) with slope parallel to given line is y = x + 5
Step-by-step explanation:
Given as :
The equation of line is x - 2 y = 6
Or, 2 y = x - 6
Or, y = × x -
i.e y = × x - 3
<u>Now, Standard equation of line in slope-intercept form </u>
y = m x + c
where m is the slope of line
And c is the y-intercept
Now, Compare given line with standard line equation
So, The slope of line y = × x - 3 = m =
<u>Again</u>
Other line is passing through points ( - 2 , 4) and is parallel to given line
∵ For parallel lines condition
The slope of both lines are equal
Let The slope of other line = M
So, from condition
M = m =
<u>Now, equation of line passing through point ( - 2 , 4) with slope </u>
So, Equation of line in slope-point form
y - = M × (x - )
Or, y - 4 = × (x - ( - 2) )
Or, y - 4 = × (x + 2 )
Or, y = × (x + 2 ) + 4
Or, y = × x + × 2 + 4
Or, y = × x + + 4
∴ y = × x + 1 + 4
i.e y = x + 5
So, Equation of other line y = x + 5
Hence, The equation of line passing through point ( - 2 , 4) with slope parallel to given line is y = x + 5 . Answer