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umka21 [38]
3 years ago
11

The formula for velocity of an object is the equals d over t where he is a velocity of the object t is the distance traveled and

t is a time in class well that distance is terrible if you had only this formula to work with what would your first step be to determine how long it takes for the light to return fitness center one additional information do you need to calculate this and solve the variable you're looking for
Mathematics
1 answer:
butalik [34]3 years ago
7 0

Answer:

(a)\ t =\frac{d}{v}

(b)\ d = vt

Step-by-step explanation:

<em>The question is mixed up with details of another question. See comment for original question</em>

<em />

<u>Given</u>

v = \frac{d}{t}

v \to velocity

d \to distance

t \to time

Solving (a): Solve for time

We have:

v = \frac{d}{t}

Cross multiply

t * v = d

Make t the subject

t =\frac{d}{v}

Solving (b): Solve for distance

We have:

v = \frac{d}{t}

Cross multiply

d = v * t

d = vt

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The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 48,564 miles, with a standard
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Answer:

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 48564, \sigma = 3293, n = 281, s = \frac{3293}{\sqrt{281}} = 196.44

What is the probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct?

This is the pvalue of Z when X = 48101. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{48101 - 48564}{196.44}

Z = -2.36

Z = -2.36 has a pvalue of 0.0091

0.0091 = 0.91% probability that the sample mean would be less than 48,101 miles in a sample of 281 tires if the manager is correct

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Step-by-step explanation:

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