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IrinaK [193]
2 years ago
14

What is the slope of the line with an equation of 5x - 3y = -12

Mathematics
1 answer:
Hoochie [10]2 years ago
5 0

Answer: m=\frac{5}{3} =1.67

Step-by-step explanation:

  1. Original equation:  5x-3y=-12
  2. Subtract 5x from both sides of the equation: -3y=-5x-12
  3. Divide both sides of the equation by -1: 3y=5x+12
  4. Divide both sides of the equation by 3 to get y on the left, leaving the equation in y=mx+b form: y=\frac{5}{3}x+4
  5. Evaluate. Slope is equal to m in this form, so the slope is m=\frac{5}{3}.

Hope this helps!

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The equation of a line is:

2y+3x=10

The line is dilated by factor 3.

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The result of dilation.

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2y+3x=10

For x=0,

2y+3(0)=10

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If the line dilated by factor 3 with origin as center of dilation, then

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Using this rule, we get

A(0,5)\to A'(3(0),3(5))

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B(2,2)\to B'(3(2),3(2))

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The dilated line passes through the points A'(0,15) and B'(6,6). So, the equation of dilated line is:

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y-15=\dfrac{-3}{2}x

Multiply both sides by 2.

2(y-15)=-3x

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2y+3x=30

Therefore, the equation of the line after the dilation is 2y+3x=30.

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