We're given the equation T = 3x + 2.
They're asking you to find the value of T when x = 1/3, so you all need to do is replace x by its value (in this case by 1/3) in the equation.
T = 3x + 2
T = 3 * (1/3) + 2
T = 3/3 + 2
T = 1 + 2
T = 3
So when x = 1/3 , T = 3.
Hope this Helps! :D
3x-8+6x=7
9x-8=7
9x=15
x=9/15
x=3/5
Answer:
<u>x² - 22x + y² - 6y + 121 = 0</u>
Step-by-step explanation:
<u>General Form of Equation</u>
<u>Solving</u>
- (x - 11)² + (y - 3)² = (3)²
- x² - 22x + 121 + y² - 6y + 9 = 9
- <u>x² - 22x + y² - 6y + 121 = 0</u>
Answer:
5/6
Step-by-step explanation:
You write the question as such: 5/9 divided by 2/3.
After that, you keep the first fraction, flip the sign and the fraction.
You will get: 5/9 multiplied by 3/2.
When you get this, you then cross multiply and simplify as such.
5/3 multiplied by 1/2.
5/6 would be your solution.