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Leviafan [203]
3 years ago
13

What number do you get when you multiply all of the numbers on a telephone's number pad?

Mathematics
1 answer:
Irina18 [472]3 years ago
7 0
Assuming that the telephone's number pad has the numbers 0<span>,1,2,3,4,5,6,7,8,9 the product will be </span><span>0</span>
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A store has apples on sale for $14.00 for 4 pounds. If an apple is approximately 5 ounces, how many apples can you buy for $84.0
adelina 88 [10]
For blank 1:
$14 for 4 pounds. so 84/14= 6, then 6x4= 24. 24 pounds of apples
For blank 2:
If an apple is approx 5 ounces, 16/5 isn't a whole number, but 15/5 is, so 3, There are about 3 apples in each pound
For blank 3:
3 apples in each pound, and you can buy 24 pounds, 3x24=72
4 0
3 years ago
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ali wants to buy a piano the piano measures 19/4 feet long she has a space 5 feet long for the paino in her house. does she have
IceJOKER [234]
Yes. This is because 19/4 as a mixed number is 4 3/4. 4 3/4 < 5. It might be a tight fit but she has enough room

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8 0
3 years ago
Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

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3 years ago
Find the product 14 × 50
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