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zysi [14]
3 years ago
7

Mike cuts a pie into 4 equal pieces. What is the angle measure of each piece

Mathematics
2 answers:
AleksandrR [38]3 years ago
7 0

Answer:

90 degrees because when you cut each of them they will each measure 90 degrees.

malfutka [58]3 years ago
5 0

Answer:

90°

hope this helps :)

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Given △QRS ~ △XYZ, what is the value of tan(Q)?
VladimirAG [237]
Since the triangles are similar the ratios of the lengths of corresponding sides are equal.

tan Q = opp/adj = RS/QS = YZ/XZ = 9/12 = 3/4
8 0
3 years ago
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Which inequality represents the value of x that ensures triangle abc exists?
olasank [31]

Answer:

Option A.

Step-by-step explanation:

According to triangle inequality theorem, a triangle exists if the sum of two sides is greater that third side.

Apply this theorem on each combination.

Case I: (2x+4)+6x>18

8x+4>18

8x>14

x>\dfrac{14}{8}

x>\dfrac{7}{4}      ...(1)

Case II: (2x+4)+18>6x

2x+22>6x

22>4x

\dfrac{22}{4}>x

\dfrac{11}{2}>x     ...(2)

Case III: 6x+18>2x+4

6x-2x>4-18

4x>-14

x>-\dfrac{14}{4}

x>-\dfrac{7}{2}     ...(3)

On combining (1), (2) and (3), we get

\dfrac{7}{4}

Therefore, the correct option is A.

3 0
3 years ago
What number do we divide by -8 to get 6?
Marina86 [1]
-48

6* -8 = -48

Hope this helps ;)
8 0
3 years ago
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Marcy played the piano for 45 minutes. She stopped playing at 4:15 p.m. At what time did she start playing the piano ?
ololo11 [35]
Well, first off 1 hr =60 minutes. 60 min - 45 min = 15 minutes extra. what is one hour before 4:15? 3:15! Add the subtracted 15 minutes to get 3:30... Hope this helps
4 0
3 years ago
30 POINTS!! ASAP! PLS SHOW WORK
sp2606 [1]

Answer:

QII

Step-by-step explanation:

We can use the acronym: ASTC or All Students Take Calculus.

The first letter of each word tells us details within a certain quadrant.

All trig functions in QI will be positive.

Only sine (and cosecant) will be positive in QII.

Only tangent (and cotangent) will be positive in QIII.

And only cosine (or secant) will be positive in QIV.

We know that tan(θ)<0. In other words, it's negative.

So, it our angle θ <em>cannot</em> be in QI or QIII.

We also know that cos(θ)<0.

So, this removes QIV, since in QIV, cosine is positive.

Therefore, the only choices that remains is QII.

In QII, sine is positive, tangent is negative, and cosine is negative.

This fits all our conditions, so θ is in QII.

And we're done!

3 0
3 years ago
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