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3 years ago

Simplify the expression

Mathematics

1 answer:

Stolb23 [73]3 years ago

8 0

Answer:

A. ${x}^{3} - x - \frac{6}{2x + 3}$

Step-by-step explanation:

$\frac{2 {x}^{4} + 3 {x}^{3} - 2 {x}^{2} - 3x - 6}{2x + 3} \\ \\ = \frac{(2 {x}^{4} + 3 {x}^{3} ) - (2 {x}^{2} + 3x) - 6}{2x + 3} \\ \\ = \frac{ {x}^{3} (2 {x} + 3 ) - x(2 {x} + 3) - 6}{2x + 3} \\ \\ = \frac{ {x}^{3} (2x + 3)}{2x + 3} - \frac{x(2x + 3)}{2x + 3} - \frac{6}{2x + 3} \\ \\ \purple { \bold{= {x}^{3} - x - \frac{6}{2x + 3} }}$

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seropon [69]

Answer:

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Step-by-step explanation:

According to the statement, let $A(x,y) = (14,21)$ and $B(x,y) = (1.25\cdot x_{A},0.75\cdot y_{A})$ . The equation of the line in point-slope form is defined by the following formula:

$y-y_{A} = m\cdot (x-x_{A})$ (1)

Where:

$x_{A}$ , $y_{A}$ - Coordinates of the point A, dimensionless.

$m$ - Slope, dimensionless.

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

In addition, the slope of the line is defined by:

$m = \frac{y_{B}-y_{A}}{x_{B}-x_{A}}$ (2)

If we know that $x_{A} = 14$ and $y_{A} = 21$ , then the equation of the line in point-slope form is:

$x_{B} = 1.25\cdot (14)$

$x_{B} = 17.5$

$y_{B} = 0.75\cdot (21)$

$y_{B} = 15.75$

From (2):

$m = \frac{15.75-21}{17.5-14}$

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By (1):

$y-21 = - \frac{3}{2}\cdot (x-14)$

The equation of the line in point-slope form is $y-21 = - \frac{3}{2}\cdot (x-14)$ .

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Answer:

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Step-by-step explanation:

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Answer:

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