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harina [27]
3 years ago
14

PLEASE HELP Which quantity is greater than |-2.4|?

Mathematics
2 answers:
irina1246 [14]3 years ago
7 0
It’s number A. I’m pretty sure
mr Goodwill [35]3 years ago
4 0

Answer:i mean i will put -1 but i am not sure tho with it yk

Step-by-step explanation:

i am so sorry if i am not right but hope u the bast tho have a good day!

You might be interested in
What is the scale factor from figure A to figure B?
SCORPION-xisa [38]

Answer:

Figure A sides are 1/4 the size of Figure B

The top of Figure A = 4, the top of Figure B = 1.

Divide 1 by 4 to get the scale factor, which is 1/4 as a fraction or 0.25 as a decimal.

Step-by-step explanation:

3 0
3 years ago
The time that it takes a randomly selected job applicant to perform a certain task has a distribution that can be approximated b
storchak [24]

Answer:

A task time of 177.125s qualify individuals for such training.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

A distribution that can be approximated by a normal distribution with a mean value of 145 sec and a standard deviation of 25 sec, so \mu = 145, \sigma = 25.

The fastest 10% are to be given advanced training. What task times qualify individuals for such training?

This is the value of X when Z has a pvalue of 0.90.

Z has a pvalue of 0.90 when it is between 1.28 and 1.29. So we want to find X when Z = 1.285.

So

Z = \frac{X - \mu}{\sigma}

1.285 = \frac{X - 145}{25}

X - 145 = 32.125

X = 177.125

A task time of 177.125s qualify individuals for such training.

7 0
3 years ago
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is f
pashok25 [27]

Answer:

0.999987

Step-by-step explanation:

Given that

The user is a legitimate one = E₁

The user is a fraudulent one = E₂

The same user originates calls from two metropolitan areas  = A

Use Bay's Theorem to solve the problem

P(E₁) = 0.0131% = 0.000131

P(E₂) = 1 - P(E₁)  = 0.999869

P(A/E₁) = 3%  = 0.03

P(A/E₂) = 30% = 0.3

Given a randomly chosen user originates calls from two or more metropolitan, The probability that the user is fraudulent user is :

P(E_2/A)=\frac{P(E_2)\times P(A/E_2)}{P(E_1)\times P(A/E_1)+P(E_2)\times P(A/E_2)}

=\frac{(0.999869)(0.3)}{(0.000131)(0.03)+(0.999869)(0.3)}

\frac{0.2999607}{0.00000393+0.2999607}

\frac{0.2999607}{0.29996463}

= 0.999986898 ≈ 0.999987

6 0
3 years ago
Please help
oksian1 [2.3K]

Answer:

1: 11√3 - 7√6

2: 11√3 - 7√6

3: -9

4:12

Step-by-step explanation:

To add radicals they need to have the same radical part for the first one we have

7√3- 4√6 + √48 - √54

We can simplify the last two into 4√3 and 3√6

So we have 7√3 - 4√6 + 4√3 - 3√6

adding similar radicals we get

11√3 - 7√6

For the second one we have 11√3 - 7√6

There's nothing we can do from here so keep that as your answer

This one is quite easy -3√9

square root of 9 is 3

so we have -3*3 which is -9

next is

4√9

same deal as the one before

3*4=12

5 0
2 years ago
Read 2 more answers
Determine whether the relation is a function. Explain why or why not.
Vitek1552 [10]

This relation is a function. This is because no x value is repeated, so it passes the vertical line test.

Here is an example of where a relation is NOT a function:

{(2, 5), (3, –5), (2, 5), (5, –5)}

Hope this helps!

3 0
2 years ago
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