3 years ago

Factor 3(x^2)+6(x^3) completely

Mathematics

1 answer:

Mandarinka [93]3 years ago

8 0

Answer:

3(x^2)(1+2x)

Step-by-step explanation:

Take 3x^2 from both function, the left will be 1+2x, so it’s the answer above

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I WILL GIVE BRAINLIest PLEASE HELP

Llana [10]

Step-by-step explanation:

t1= 2-3-6=-7

t2= 8-6-6=-4

t3=18-9-6=3

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3 years ago

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Solve G(x) for the given domain. Include all of your work in your final answer. Submit your solution. G(x) = 3x2 - 2x - 1 G(a +

Arada [10]

Answer:

g(a+b) = 3a² + 3b² - 6ab - 2a - 2b - 1

Step-by-step explanation:

Given, function:

g(x) = 3x² -2x - 1

For the domain x= (a+b), the g(x) is:

g(a+b) = 3*(a+b)² - 2(a+b) - 1 = 3a² + 3b² - 6ab - 2a - 2b - 1

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4 years ago

Choose the following ratios as a fraction: 20 correct out of 25 problems (three are correct)

Sergio039 [100]

Answer:

4/5

Step-by-step explanation:

It’s 20/25 but you can simplify. Divide both by 5 and you get 4/5.

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3 years ago

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----- Negative 5 minus negative 1 equals

Vika [28.1K]

Answer:-4

Step-by-step explanation:

Since both are negative already, and you ain’t subtracting to a negative its -4.

(-5)-(-1)=-4

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3 years ago

Determine the region of the xy-plane where the solution of the DE would have a unique solution passing through the point (x0,y0)

Virty [35]

Answer:

given equation,

$(9-y^2)\dfrac{dy}{dx}= x^4\\(9-y^2)dy = x^4 dx\\\int (9-y^2)dy =\int x^4 dx\\9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+C$

so,

the given point from where the region is passing through is (x₀, y₀)

hence, the unique equation comes out to be

$9y_0 -\dfrac{y_0^3}{3} = \dfrac{x_0^5}{5}+C$

$C = 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}$

hence unique equation,

$9y -\dfrac{y^3}{3} = \dfrac{x^5}{5}+ 9y_0 -\dfrac{y_0^3}{3}-\dfrac{x_0^5}{5}$

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3 years ago