Question

Consider the equation 7*e^0.1t=47 solve the equation for t. epress the solution as a logarithm in base-e

Answer 1

An equation is formed of two equal expressions. The equation 7*e^0.1t=47 can be expressed as t=[ln (47/7)]/0.1.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

The equation 7*e^0.1t=47 in terms of logarithm in terms of base-e can be solved as,

$7e^{0.1t}=47\\\\e^{0.1t}=\dfrac{47}{7}\\\\0.1 t = {\rm ln}(\dfrac{47}{7})\\\\t = \dfrac{ {\rm ln}(\frac{47}{7})}{0.1}$

Hence, the equation 7*e^0.1t=47 can be expressed as t=[ln (47/7)]/0.1.

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