Answer:
Problem 13: yes
Problem 14: no
Step-by-step explanation:
Problem 13:
Plug the values of x and y to solve.
-23 = -7(5) + 12
-23 = -35 + 12
-23 = -23
The values are equal, so the coordinates <u>do</u> solve the equation. It's a yes.
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Problem 14:
Plug the values of x and y to solve.
-9 = -7(-3) + 12
-9 = 21 + 12
-9 = 33
The values are not equal, so the coordinates <u>do not</u> solve the equation. It's a no.
hope this helps :)
The last one , because I will now solve it for you and prove therefore.
x²–4x+5=0;
D=(–4)²–4•5=16–20= –4= (2i)².
So:
x1= (4–2i)/2= 2–i
x2= (4+2i)2= 2+i.
This is the whole answer....
Three other u will solve by yourself and have roots which will not be suitable.
Answer:
-8^
Step-by-step explanation:
-8^
A right triangle does have perpendicular line because they can cross if the lines go on forever
A quadilateral is a 4 sided shape so if you talking about the square or a rectangle or a parralelogram no it does not have perpendicular sides BUT if you are talking about a trapezoid it does have pependicular side
HOPE THIS HELPS!!!!!!! ;-)
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