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2 years ago

Question 6 (2 points)

Mathematics

1 answer:

Orlov [11]2 years ago

6 0

Answer:

Blank 1: (-7,0)

Blank 2: (-1,0)

Step-by-step explanation:

Plug x=0 into the equation and solve the resulting equation y=7 for y

Plug y=0 into the equation and solve the resulting equation 0=(x+1)(x+7) for x

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Savannah had 40 iris blooms last year this year she had 15% more iris blooms how many more hours blooms did Savannah have this y

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Answer:

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Step-by-step explanation:

40 times .15 is 6

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Your patio is 12 feet by 15 feet. After remodeling, the new dimensions are 18 feet by 22 feet. By how many square feet have you

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<h3>Answer: 216 square feet</h3>

Work Shown:

Old area = 12*15 = 180 square feet

New area = 18*22 = 396 square feet

Difference = New - Old = 396 - 180 = 216

The patio's area increased by 216 square feet.

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A coordinate plane graph is shown. Point C is at negative 4 comma 3. Point D is at 1 comma 0. A segment connects the two points.

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Can someone help please (highlighted in blue)

Annette [7]

$\implies {\blue {\boxed {\boxed {\purple {\sf {B)\:10}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$4 + 3 \: ( \: 10 - {2}^{3} \: )$

➺ $\: 4 + 3 \: ( \: 10 - 2 \times 2 \times 2 \: )$

➺ $\: 4 + 3 \: ( \: 10 - 8 \: )$

➺ $\: 4 + 3 \: ( \: 2 \: )$

➺ $\: 4 + 6$

➺ $\: 10$

$\sf\pink{PEMDAS\: rule.}$

P = Parentheses

E = Exponents

M = Multiplication

D = Division

A = Addition

S = Subtraction

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

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3 years ago

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X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y

andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

$\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}$

Part b.

Consider V(3X + 2Y)

$\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}$

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

$3 X+2 Y \sim N(18,77)$

Thus,

$P(3 X+2 Y < 18)=0.5$

Part d.

Consider P(3X + 2Y < 28)

$Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}$

$\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}$

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

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The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

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1 year ago