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3 years ago

11

Show all steps! K-2= 6

2 answers:

Tanzania [10]3 years ago

5 0

K=8

Add the 2 to 6 on the other side of the =sign
Which leaves K alone and K equals 8

Sloan [31]3 years ago

3 0

Answer:

8

Step-by-step explanation:

k - 2 = 6

+2 +2

k = 8

Whenever solving for these your first goal is to get rid of any constants isolating the variable by itself. To get rid of -2 we add 2 to both sides, whatever we do to the left we do to the right and vice versa. When we add 2 to 6 we get 8 and that is how we got our answer.

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Which investment might have more hidden costs than others?

GuDViN [60]

Answer:

C. Mutual Funds

Step-by-step explanation:

If you look it up, Mutual Funds seem to have more secrets and fees than other funds.

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3 years ago

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gayaneshka [121]

Answer:

point C

Step-by-step explanation:

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3 years ago

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Help I’ll give you Brainleiest

yan [13]

Answer:

<em>6 cm </em>

Step-by-step explanation:

<u><em>I don't know may I use the trigonometry functions, therefor I'm going to use Pythagorean theorem and property of 30°-60°-90° triangle.</em></u>

m∠ACB = 120° ⇒ m∠ACD = 60° ⇒ m∠DAC = 30°

DC is opposite to 30° angle ⇒ AC = CB = 8 cm

From ΔADC: AD² = 64 - 16 = 48 ; AD = 4√3 cm

ΔACB is isosceles ⇒ m∠CAB = m∠CBA = 30°

m∠DAH = m∠DAC + m∠CBA = 2(30°) = 60° ⇒ m∠ADH = 30° ⇒ AH = 4√3 ÷ 2 = 2√3 cm

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6 0

3 years ago

Graph the function, identify if it represents exponential growth or decay, and identify domain and range. See picture

Brrunno [24]

Answer:

a. Decay

b. 0.5

c. 4

Explanation:

If we have a function of the form

$y=ab^x$

then

a = intital amount

b = growth / decay rate factor

x = time interval

If b > 1; then the equation is modelling growth. If b < 0, then the equation is modelling decay.

Now in our case, we have

$y=4(\frac{1}{2})^x$

Here we see that

inital amount = a = 4

b = 1/ 2 < 0, meaning the function is modeling decay

decay factor = b = 1/2

Therefore, the answers are

a. Decay

b. 0.5

c. 4

4 0

1 year ago

Factorise 3(3x-y)-(y-3x)

snow_lady [41]

Answer:

4(3x-y)

Step-by-step explanation:

Given:

$\displaystyle \large{3(3x-y)-(y-3x)}$

To factor this kind of expression, first, find the common factor.

$\displaystyle \large{3(3x-y)-(-3x+y)}\\\displaystyle \large{3(3x-y)+(3x-y)}$

Notice that in the expression, we have both same (3x-y). Therefore, (3x-y) is our factor.

Let u = 3x-y

$\displaystyle \large{3u+u}\\\displaystyle \large{4u}$

Change u back to 3x-y:

$\displaystyle \large{4(3x-y)}$

Therefore, the factored expression is 4(3x-y).

4 0

2 years ago