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3 years ago

What are the x-intercepts of the graph of y

Mathematics

2 answers:

zysi [14]3 years ago

7 0

JLSLDKSKDDODODKDKDMXMXMDMDDKD

lora16 [44]3 years ago

7 0

Answer:

The answer is D

Step-by-step explanation:

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Find the slop of the line passing through the given points (2,3),(-1,-6)

professor190 [17]

Slope is rise over run

I would suggest writing the coordinate that is farthest to the left first so it is easier to visualize (-1,-6),(2,3)
as you go to the right, it goes over three, and up 9
9/3 simplifies to 3
the slope is 3

5 0

3 years ago

A set of equations is given below:

nirvana33 [79]

Answer:

Step-by-step explanation:

y=y

x+9 = 2x + 2

x-2x=-9+2

-x=-7

x=7

3 0

3 years ago

Write the equation of each line in slope-intercept form.<br> (If possible please show work)

Alik [6]

Answer:

y = 5x - 4

Step-by-step explanation:

Step 1: Write known variables

m = 5

y = 5x + b

Step 2: Find <em>b</em>

6 = 5(2) + b

6 = 10 + b

b = -4

Step 3: Rewrite equation

y = 5x - 4

7 0

4 years ago

This parabola has<br> x-intercepts

slega [8]

Answer:

see the explanation

Step-by-step explanation:

we have the quadratic equation

$y=-16x^{2} +32x-10$

This is a vertical parabola open downward

The vertex is a maximum

Find the x-intercepts of the quadratic equation

The x-intercepts are the values of x when the value of y is equal to zero

For y=0

$-16x^{2} +32x-10=0$

Solve the quadratic equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16x^{2} +32x-10=0$

$a=-16\\b=32\\c=-10$

substitute in the formula

$x=\frac{-32(+/-)\sqrt{32^{2}-4(-16)(-10)}} {2(-16)}$

$x=\frac{-32(+/-)\sqrt{384}} {-32}$

$x=\frac{-32(+/-)8\sqrt{6}}{-32}$

$x=\frac{-32(+)8\sqrt{6}}{-32}=\frac{32(-)8\sqrt{6}}{32}=0.39\ sec$

$x=\frac{-32(-)8\sqrt{6}}{-32}=\frac{32(+)8\sqrt{6}}{32}=1.61\ sec$

therefore

This parabola has two x-intercepts representing the times when the dolphin's height above water is zero feet

8 0

3 years ago

Read 2 more answers

F(x)=x^2-2x+3 g(x)=x^2-2x-4 Find f(g(-2)

olga55 [171]

Answer:

$f(g(-2))=11$

Step-by-step explanation:

We are given the two functions:

$f(x)=x^2-2x+3\text{ and } g(x)=x^2-2x-4$

And we want to find:

$f(g(-2))$

We will find g(-2) first. So:

$g(-2)=(-2)^2-2(-2)-4=4+4-4=4$

Thus:

$f(g(-2))=f(4)$

Evaluate:

$f(4)=(4)^2-2(4)+3=16-8+3=11$

Therefore:

$f(g(-2))=11$

4 0

3 years ago