If you know how to this and can help that would be so great...also please take a look at my last question Thanks

Help me with #5 pleaseeeeeeeeeee

earnstyle [38]

Answer:

$\angle 1 = 45$ degrees

Step-by-step explanation:

Sum of 3 angles in a triangle is 180..

The angles given are:

60

7x + 12

1

So we sum to 180 and write:

$60+7x+12+\angle 1=180\\72+7x+\angle 1=180\\7x+\angle 1=108$

Also, straight angle is 180 degrees, thus Angle 1 and (14x + 9) angle is sum to 180, thus we can write:

$14x+9+\angle 1=180\\14x + \angle 1=171$

Or we can write this as:

$14x + \angle 1=171\\\angle 1 = 171 - 14x$

We substitute this expression for Angle 1 into 1st equation we got and solve for x first,

$7x+\angle 1 = 108\\7x+( 171 - 14x)=108\\-7x=-63\\x=9$

Since x = 9, the angle "14x + 9" would be:

14(9) + 9 = 135

Hence Angle 1 would be:

$\angle 1 + 14x + 9 = 180\\\angle 1 + 135 = 180\\\angle 1 = 45$

6 0

3 years ago

Find the least common multiple of 12 and 18?

Evgesh-ka [11]

36 is the correct answer

8 0

3 years ago

WHOEVER ANSWERS FIRST GETS BRAINLIEST!!!!

Ratling [72]

Answer:

A, C and E are true.

Step-by-step explanation:

The domain is a set of natural numbers.

The recursive formula is correct:

When x = 1, f(x) = 4 and f(x + 1) = f(2) = 3/2 f(x) = 3/2 * 4 = 6.

It is also true for the other points on the graph.

D is incorrect.

E is correct exponential growth with the formula 4(3/2)^(x-1).

6 0

3 years ago

I need help, please I have until 9 p.m. to finish it number 3 homework

sergeinik [125]

Answer: 1/3

<u>Step-by-step explanation:</u>

When adding or subtracting fractions, they must have the same denominator.

$\dfrac{5}{9}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{5}{9}\bigg(\dfrac{6}{6}\bigg)-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{18}{54}}=\dfrac{12}{54}\\\\\\\text{Simplify}\quad \dfrac{18}{54}\div \dfrac{18}{18}\quad =\large\boxed{\dfrac{1}{3}}$

6 0

3 years ago

A concert hall has 8,000 seats and two categories of ticket prices, $29 and $34. Assume that all seats in each category can be s

Greeley [361]

Using a system of equations, it is found that:

For a profit of $255,000, 3400 tickets of $29 and 4600 tickets of $34 must be sold.
For a profit of $271,000, 200 tickets of $29 and 7800 tickets of $34 must be sold.
For a profit of $235,000, 7400 tickets of $29 and 600 tickets of $34 must be sold.