Please help veryyy urgent due today!!!!!!

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

42 is the answer....

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A truck is rented at $40 per day plus a charge per mile of use. The truck traveled 15 miles in one day, and the total charge was

lesantik [10]

15x+40=115
15x+40-40=115-40
15x=75
15/15 x=75/15
x= 5

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3 years ago

Chrissy wants to spend at most $45 on dinner. If she bought an entree for $20 and she wants to buy mini appetizers for $3 each,

Sever21 [200]

Answer:

Step-by-step explanation:

Chrissy can buy 8 mini appetizers.......because

45 - 20 = 25

25 divide 3 = 8.3333333333333 so the most she can buy is 8..

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A statistics textbook chapter contains 60 exercises, 6 of which are essay questions. A student is assigned 10 problems. (a) What

Scilla [17]

Answer:

a) P=0.3174

b) P=0.4232

c) P=0.2594

d) The shape of the hypergeometric, in this case, is like a binomial with mean np=1.

Step-by-step explanation:

The appropiate distribution to model this is the hypergeometric distribution:

$P(X=x)=\frac{\binom{s}{x}\binom{N-s}{M-x}}{\binom{N}{M}}=\frac{\binom{6}{x}\binom{54}{10-x}}{\binom{60}{10}}$

a) What is the probability that none of the questions are essay?

$P(X=0)=\frac{\binom{6}{0}\binom{54}{10-0}}{\binom{60}{10}}\\\\P(X=0)=\frac{1*(54!/(10!*44!)}{60!/(10!*50!)} =\frac{2.3931*10^{10}}{7.5394*10^{10}} = 0.3174$

b) What is the probability that at least one is essay?

$P(X=1)=\frac{\binom{6}{1}\binom{54}{9}}{\binom{60}{10}}\\\\P(X=1)=\frac{6*(54!/(9!*43!)}{60!/(10!*50!)} =\frac{3.1908*10^{10}}{7.5394*10^{10}} =0.4232$