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insens350 [35]
3 years ago
14

What patterns do you find within the fractions in the inch on the ruler?

Computers and Technology
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

The markings on a standard ruler represent the fractions of an inch. The markings on a ruler from the start to the 1″ mark are: 1⁄16“, 1⁄8“, 3⁄16“, 1⁄4“, 5⁄16“, 3⁄8“, 7⁄16“, 1⁄2“, 9⁄16“, 5⁄8“, 11⁄16“, 3⁄4“, 13⁄16“, 7⁄8“, 15⁄16“, and 1”.

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Imagine the user types in a complete sentence, but we want to read only the first word and place it in the String variable word.
Vladimir [108]

Answer:

import java.util.Scanner;

public class FirstWord {

   public static void main(String[] args) {

       //NOW YOU WANT TO COLLECT INPUTS FROM THE STUDENT OR USER

       //IMPORT THE SCANNER CLASS FIRST  outside your class

       // THEN YOU CREATE AN OBJECT OF THE SCANNER CLASS

       Scanner input = new Scanner(System.in);

       

       //CREATE A VARIABLE TO HOLD THE USER INPUT

       String text = input.nextLine();

       

       //The variable holder will be used to store characters from the for loop

       String holder="";

       

       //Create a for loop that loops through the user's input

       for(int i=0; i<text.length(); i++){

           //As the loop increases, we get the character in the user's input and store them one by one in the variable holder

           holder+=text.charAt(i);

           if(text.charAt(i)==' '){

               //If the loop encounters a space, it means a complete word has been gotten from the user's input

               //Then the break below Breaks the loop, and the loop stops running

               break;

           }

       }

       System.out.println(holder);

}

Explanation:

text.length() returns the length of the sequence of characters present in length

text.charAt(a number) Returns the char value at the specified index. An index ranges from 0 to length() - 1. The first char value of the sequence is at index 0, the next at index 1, and so on, as for array indexing.

Create a for loop

How does a for loop work?

It collects a starting point, an end point and an increment respectively....all these are passed in as arguments into the for loop

For example, the code above starts from 0, calculates the number of characters in the user's input and sets it as the end point, the loop runs from zero to the length of the text of the user...

Note: i++ in the loop is the increment, it means the loop increases by 1

8 0
3 years ago
Which of the following statements are true about the Internet?
Arlecino [84]
1, 2, and 3 are true
6 0
3 years ago
Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)
Mnenie [13.5K]

Answer:

(1)Minterms complement = XYZ (2) Compliment of Minterms = Σm(0,1, 2 , 4 , 6) (3) (X+Y+Z) (4) Minimized SOP = Z + XY

Manterms = πM

Explanation:

Solution

Recall that:

Given the function F (X, Y , Z)=Σm(0,1, 2 , 4 , 6)

(1) Canonical Disjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as minterms

In Minterm we assign 'I' to each uncomplimented variable and '0' to each complemented/complementary variable

For the given question stated we ave the following:

Minterms = XYZ, XYZ, XYZ, XYZ, XYZ.

(2) Canonical Conjunctive Normal Form: In boolean algebra, the boolean function can be expressed as Canonical Disjunctive form known as maxterms.

In Maxterms we assign '0' to each uncomplimented variable and '1' to each complemented/complementary variable

Compliment of Minterms = Σm(0,1, 2 , 4 , 6)

Maxterms = πM

Note: Kindly find an attached copy of the complete solution to this question below.

6 0
3 years ago
How to the inverse function of f(x)=x2 +1 ,x&gt;o
Sindrei [870]
    f(x) = x² + 1, x > 0
       y = x² + 1
       x = y² + 1
   x - 1 = y²
√x - 1 = y
√x - 1 = f(x), x > 1
5 0
3 years ago
An IPv4 address has 32 bits, so there are 232 (over 4 billion) possible IPv4 addresses. Since the Internet is gaining devices qu
Vladimir [108]

Answer:

Explanation:IPv4 is almost used up due to the constant increase in devices so therefore IPv6 was implemented to combat this issue, IPv6 uses 128 bit addresses, allowing 3.4 x 1038 unique IP addresses. This is equal to 340 trillion trillion trillion IP addresses. IPv6 is written in hexadecimal notation, separated into 8 groups of 16 bits by the colons, thus (8 x 16 = 128) bits in total. Which essentially means both me and you wont see IPv6 run out in our life times nor will you kids kids.

4 0
2 years ago
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