3 years ago

Given Set $P:\ 3,\ 4,\ 7,\ 8,\ 8$ and Set $Q:\ 0,\ 0,\ 1,\ 1,\ 3,\ 7$.

1 answer:

Volgvan3 years ago

3 0

Answer:

1:6

2:2

3:4, it's twice the MAD.

Step-by-step explanation:

6-2=4

MAD: 2

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eduard

$32/4 = $8 per ticket

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3 years ago

Vlad [161]

I wonder if you mean to write $\sqrt[3]{256}$ in place of $3\sqrt{256}$ ...

If you meant what you wrote, then we have

$\sqrt{256}=\sqrt{16^2}=16$

$3\sqrt{256}=3\cdot16=48$

If you meant to write $\sqrt[3]{256}$ (the cube root of 256), then we could go on to have

$\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4$

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3 years ago

nydimaria [60]

Answer:

The anwser is B

Step-by-step explanation:

yes, because you need to convert the repeating number into a decimal. In this case, you can assume that x is the fraction form of 0.7 repeating.

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3 years ago

Elina [12.6K]

10% of 10 is 10%*10 which is 1 :)

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3 years ago

tekilochka [14]

Answer:

It looks like the slope is -2

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3 years ago

Given Set \(P:\ 3,\ 4,\ 7,\ 8,\ 8\) and Set \(Q:\ 0,\ 0,\ 1,\ 1,\ 3,\ 7\).