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Anit [1.1K]
3 years ago
7

Divide the polynomails. your answer should be in the form p(x)+k/x-2 where p is a polynomial and k is an integer.

Mathematics
1 answer:
Tpy6a [65]3 years ago
6 0

Answer:

it’s...whatever it is

Step-by-step explanation:

it can’t be any clearer

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Which of the following could be the sides of a right triangle? Check all that apply.
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A. & D. are the correct answers

To answer this, you square the first 2 numbers in the sequence, and then add them together. You then square the 3rd number and put it equal to the first numbers that you added together. If the two sides equal each other, it is correct!

Ex.:

10, 24, 26

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What is 1,364 divided by 62
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The answer is ...... 22
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Consider the number 284,682
Law Incorporation [45]

Answer:

Hundred thousand's 200000

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5 0
3 years ago
Read 2 more answers
Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a me
Maslowich

Answer:

The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357

Step-by-step explanation:

For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.

We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by

W = \frac{X-\mu}{\sigma} = \frac{X-10000}{100}

We have

P(X>10110) = P(\frac{X-10000}{100} > \frac{10110-10000}{100}) = P(W > 1,1) = 1-\phi(1,1) = 1-0.8643 = 0.1357

Where \phi is the cummulative distribution function of a standard normal distribution. The values of \phi are well known and they can be found in the attached file.

We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.

Download pdf
4 0
3 years ago
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