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vivado [14]
2 years ago
6

Find the missing side lengths. Leave your answers as a radicals In simplest form

Mathematics
1 answer:
trapecia [35]2 years ago
6 0

Answer:

g dyurirrirjdjfffggggtr

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What expression is the simplified form of “-12+5a-a-6a+8a+8+3a”? Please explain your reasoning.
kramer

Combine like terms:

-12 + 5a - a - 6a + 8a + 8 + 3a

-12 + 5a - a - 6a + 8a + 8 + 3a

5a - a = 4a

4a - 6a = -2a

-2a + 8a = 6a

6a + 3a = 9a

-12 + 8 = -4

Answer

9a - 4

4 0
3 years ago
Read 2 more answers
Convert the following degree measure to radian measure. 90 degrees
Ray Of Light [21]
90 degrees converted to radians is pi/2 or π/2 radians.
4 0
3 years ago
How many buttons did Anne sew?<br> Rate: 8 buttons per minute Time: 7 minutes
olganol [36]

Answer:

42 buttons

Step-by-step explanation:

8 x 7 = 42

42 buttons

Hope that helped have a nice day

Can I have brainliest btw?

8 0
3 years ago
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Part 1: Use the information provided to write the standard form equation of each circle. Please show the work.
dusya [7]

Answer:

1. (x + 2)² + (y - 9)² = 64

2. (x + 6)² + (y - 9/2)² = 100

3. (x - 15)² + (y + 10)² = 1

Step-by-step explanation:

Equation of a circle:

(x - h)² + (y - k)² = r²

1. Center: (-2, 9), Radius: 8

(x - (-2))² + (y - 9)² = 8²

(x + 2)² + (y - 9)² = 64

2. Center: (-6, 9/2), Radius: 10

(x - (-6))² + (y - (9/2))² = 10²

(x + 6)² + (y - 9/2)² = 100

3. Center: (15, -10), Radius: 1

(x - 15)² + (y - (-10))² = 1²

(x - 15)² + (y + 10)² = 1

4 0
3 years ago
(Ross 5.15) If X is a normal random variable with parameters µ " 10 and σ 2 " 36, compute (a) PpX ą 5q (b) Pp4 ă X ă 16q (c) PpX
pochemuha

Answer:

(a) 0.7967

(b) 0.6826

(c) 0.3707

(d) 0.9525

(e) 0.1587

Step-by-step explanation:

The random variable <em>X</em> follows a Normal distribution with mean <em>μ</em> = 10 and  variance <em>σ</em>² = 36.

(a)

Compute the value of P (X > 5) as follows:

P(X>5)=P(\frac{x-\mu}{\sigma}>\frac{5-10}{\sqrt{36}})\\=P(Z>-0.833)\\=P(Z

Thus, the value of P (X > 5) is 0.7967.

(b)

Compute the value of P (4 < X < 16) as follows:

P(4

Thus, the value of P (4 < X < 16) is 0.6826.

(c)

Compute the value of P (X < 8) as follows:

P(X

Thus, the value of P (X < 8) is 0.3707.

(d)

Compute the value of P (X < 20) as follows:

P(X

Thus, the value of P (X < 20) is 0.9525.

(e)

Compute the value of P (X > 16) as follows:

P(X>16)=P(\frac{x-\mu}{\sigma}>\frac{16-10}{\sqrt{36}})\\=P(Z>1)\\=1-P(Z

Thus, the value of P (X > 16) is 0.1587.

**Use a <em>z</em>-table for the probabilities.

8 0
3 years ago
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