<span>6x^2y + 8x^2 − 30y − 40
= 2x^2(3y + 4) - 10(3y + 4)
= (2x^2 - 10)(3y + 4)
= 2(x^2 - 5)(3y + 4)</span>
6! = 6 * 5 *4*3*2*1 =720
8p5 = 8*7*6*5*4 = 6720
12C4 = (12p4)/4! = (12*11*10*9)/4*3*2*1 = 495
Answer:
C. 40in
Step-by-step explanation:

so...


576+1024=1600

the missing side = 40in
Answer:
The height of the tree=8.42 m
Step-by-step explanation:
We are given that
Height of Joshua, h=1.45 m
Length of tree's shadow, L=31.65 m
Distance between tree and Joshua=26.2 m
We have to find the height of the tree.
BC=26.2 m
BD=31.65m
CD=BD-BC
CD=31.65-26.2=5.45 m
EC=1.45 m
All right triangles are similar .When two triangles are similar then the ratio of their corresponding sides are equal.


Substitute the values



Hence, the height of the tree=8.42 m