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saveliy_v [14]
3 years ago
15

Please help thank you! :)

Mathematics
1 answer:
IrinaK [193]3 years ago
6 0

Answer:

126.5

Step-by-step explanation:

The polygon is made up of a rectangle and a triangle.

rectangle: 11 cm by 8 cm

triangle: base = 11 cm; height = 7 cm

area = LW + bh/2

area = 11 cm * 8 cm + (11 cm)(7 cm)/2

area = 88 cm^2 + 77/2 cm^2

area = 88 cm^2 + 38.5 cm^2

area = 126.5 cm^2

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Pls help, i'll give you a brainliest 4 answer <3
babymother [125]

Answer:

x = 45 \ \& \ y = 5

Step-by-step explanation:

The system of linear equations in two variables is ,

\begin{cases} x = 9y \cdots (i)\\ x - 5y = 20\cdots (ii) \end{cases}

We can easily solve out this Question using substitution method . For that , substituting x = 9y from equation (i) to equation (ii) , we have ,

\implies x - 5y = 20 \\\\\implies 9y - 5y = 20 \\\\\implies 4y = 20 \\\\\implies y =\dfrac{20}{4}\\\\\implies\boxed{\boxed{ y = 5 }}

Substituting this value in (i) ,

\implies x = 9y \\\\\implies x = 9\times 5 \\\\\implies \boxed{\boxed{ x = 45 }}

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3 years ago
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do u still need help with this

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3 years ago
A parabolà can be drawn given a focus of (7,9) and a
NeTakaya

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keeping in mind the vertex is half-way between these two fellows, Check the picture below.

\bf \textit{vertical parabola vertex form with focus point distance} \\\\ 4p(y- k)=(x- h)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h,k+p)}\qquad \stackrel{directrix}{y=k-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\cap}\qquad \stackrel{"p"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill

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6 0
4 years ago
Help please thank you!
PSYCHO15rus [73]

Answer: Possibly the first

Step-by-step explanation:

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3 years ago
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Answer:

Step-by-step explanation:

18 : 63

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Option C is the correct answer

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