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avanturin [10]
3 years ago
11

PLZ HELPPPP C candies cost 5 dollars. how much money would 12 dollars cost?

Mathematics
2 answers:
vitfil [10]3 years ago
7 0
If you mean how much money would 12 candies cost than it would be 12 over c times 5

12/c • 5
Sladkaya [172]3 years ago
4 0
12 divided by 5 = 2.4
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Please hellp I’m really confused
Viefleur [7K]

Answer:

Start at the origin and plot the points.

Step-by-step explanation:

For A, start at the origin and then go 4 units to the left.

For B, start at the origin and then go 4 units up.

For D, start at the origin and then go 4 units to the right.

For C, start at the origin and then go 4 units down.

6 0
2 years ago
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Fred buys flags from a manufacturer for f dollars each and then sells the flags in his store for a 26%markup.
Mashutka [201]

Answer:

the markup is 1.26 (the amount added is .26)

1.26x (when x is the price Fred buys them for from the manufacturer)

1.26(40)

$50.40 is the retail price

50.4-40

$10.40 is the markup

Step-by-step explanation:

The 26% markup means that he is selling the flags 26% above the cost.

So, the cost would represent 100%, which is 1, and 26% of markup in decimal number is 0.26.

The price including the markup would be 1.26 as decimal or 126% as percentage.

The problem states that the cost is unknown, so we represent that with a variable x. The retail price would be 1.26x, which is 126% per flag.

Finally, if Fred paid $40 per flag, the actual retail price would be:

1.26($40)=$50.40.

With $10.40 of markup.

5 0
3 years ago
What's the area of the entire shape?
Svetach [21]

Answer:

30

Step-by-step explanation:

you need to multiply its length by its with

7 0
3 years ago
Please i need help finishing this test i’ll give brainly to a correct answer
rjkz [21]

imma go with my gut and say b :?

7 0
3 years ago
What is the true solution to 3 in 2 + in 8 = 2 in (4x)
11Alexandr11 [23.1K]
The first step for solving this equation is to determine the defined range.
3㏑(2) + ㏑(8) = 2㏑(4x), x > 0
Write the number 8 in exponential form.
3㏑(2) + ㏑(2³) = 2㏑(4x)
Using ㏑(a^{x}) = x × ㏑(a),, transform the expression.
3㏑(2) + 3㏑(2) = 2㏑(4x)
Now collect the like terms on the left side of the equation.
6㏑(2) = 2㏑(4x)
Switch the sides of the equation.
2㏑(4x) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the left side of the equation.
㏑((4x)²) = 6㏑(2)
Using x × ㏑(a) = ㏑(a^{x}),, transform the expression on the right side of the equation.
㏑((4x)²) = ㏑(2^{6})
Since the bases of the logarithms are the same,, you need to set the arguments equal.
(4x)² = 2^{6}
Take the square root of both sides of the equation and remember to use both the positive and negative roots.
4x = +/- 8
Now separate the equation into 2 possible cases.
4x = 8
4x = -8
Solve the top equation for x.
x = 2
Solve the bottom equation for x.
x = 2
         , x > 0
x = -2
Lastly,, check if the solution is in the defined range to find your final answer.
x = 2
This means that the correct answer to your question is x = 2.
Let me know if you have any further questions
:)
5 0
3 years ago
Read 2 more answers
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