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2 years ago

Solve for z THANK U SM I WILL MARK BRAINILIEST

Mathematics

2 answers:

Anit [1.1K]2 years ago

3 0

Answer:

z=7

Step-by-step explanation:

Combine like terms: 2z=14

Reduce the greatest common factor on both sides of the equation z=7

answer: z= 7

Ugo [173]2 years ago

3 0

Answer:

z = 7

Step-by-step explanation:

6z + z - 4z + 4z - 5z = 14

Collect like terms

6 + 1 - 4 + 4 - 5

-4 and 4 cancel out each other so remove it from the equation

6 + 1 - 5 = 2

2z = 14

Divide by 2 to isolate z

z= 7

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Thepotemich [5.8K]

Answer: the sequence is to divide by 3 and it gets smaller and smaller by dividing by three I don't think there is an end to it.

Step-by-step explanation:

9/3=3

3/3=1

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1/3/3=1/9

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2 years ago

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dolphi86 [110]

Answer:

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2 years ago

How do you solve the literal equation for g=6x solve for x

Artemon [7]

You would solve it just like how you would solve it with numbers.Solve it like how you would solve this 7=6*2.

8 0

3 years ago

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Given the relationship x2 + 3y2 =12, with y > 0 and dx, dt = 2 units/min., find the value of dy, dt at the instant y = 1 unit

matrenka [14]

$\bf x^2+3y^2=12\implies \stackrel{chain~rule}{2x\cfrac{dx}{dt}}+3 \stackrel{chain~rule}{\left(2y\cfrac{dy}{dt}\right)}=0
\\\\\\
2x\cfrac{dx}{dt}+6y\cfrac{dy}{dt}=0
\implies 
6y\cfrac{dy}{dt}=-2x\cfrac{dx}{dt}\implies \cfrac{dy}{dt}=\cfrac{-2x\frac{dx}{dt}}{
6y\frac{dy}{dt}}
\\\\\\
\boxed{\cfrac{dy}{dt}=-\cfrac{x\frac{dx}{dt}}{3y}}\\\\
-------------------------------$

$\bf \textit{now, when y = 1, what is \underline{x}?}\qquad x^2+3y^2=12\implies x^2+3(1)^2=12
\\\\\\
x^2=9\implies x=\sqrt{9}\implies x=3\\\\
-------------------------------\\\\
\begin{cases}
y=1\\
x=3\\
\frac{dx}{dt}=2
\end{cases}\implies \cfrac{dy}{dt}=-\cfrac{3\cdot 2}{3\cdot 1}\implies \cfrac{dy}{dt}=-2$

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2 years ago

−30=5(x+1) please simplify this for khan academy. org

brilliants [131]

Answer:

-7 =x

Step-by-step explanation:

−30=5(x+1)

Divide each side by 5

−30/5=5/5 (x+1)

-6 = x+1

Subtract 1 from each side

-6-1 = x+1-1

-7 =x

4 0

3 years ago

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