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3 years ago

8

Select all the angles that are supplementary to angle 1.

1 answer:

Doss [256]3 years ago

8 0

M and n are the answer

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Which line is perpendicular to a line that has a slope of -1/3?

Sliva [168]

Answer:

Option (c)

Step-by-step explanation:

Slope of a line that passing through two points M(-1, 4) and N(2, -5),

$m_1$ = $\frac{y_2-y_1}{x_2-x_1}$

= $\frac{-1-2}{4+5}$

= -( $\frac{3}{9}$ )

= - $\frac{1}{3}$

To find the line perpendicular line to MN we will use the property,

$m_1\times m_2=-1$

Where $m_1$ and $m_2$ are the slopes of two perpendicular lines.

Slope of line perpendicular to MN $(m_2)$ will be,

$-\frac{1}{3}\times m_2=-1$

$m_2=3$

Slope of line joining two points J(-3, -4) and K(3, -2),

Slope = $\frac{-4+2}{-3-3}=\frac{1}{3}$

Slope of line joining two points A(-3, 2) and B(3, 0)

Slope = $\frac{2-0}{-3-3}=-\frac{1}{3}$

Slope of the line joining points E(0, -3) and F(2, 3),

Slope = $\frac{-3-3}{0-2}$ = 3

Therefore, line EF is perpendicular to the line MN.

Option (c) is the answer.

8 0

3 years ago

Solve the equation 21 + x = 26

klemol [59]

Answer:

x = 26 - 21 = 5

3 0

4 years ago

Read 2 more answers

Either enter an exact answer in terms of \piπ or use 3.143.14 for \piπ and enter your answer as a decimal.

BaLLatris [955]

Answer:

The area of the shape is $27 \pi\ units^{2}$

Step-by-step explanation:

we know that

The area of the shape is the area of a three quarter of circle

The area of a three quarter of circle is equal to

$A=\frac{3}{4}\pi r^{2}$

we have

$r=6\ units$

substitute

$A=\frac{3}{4}\pi (6^{2})=27 \pi\ units^{2}$

3 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5x%20%2B%2050%7D%7Bx%20%2B%205%7D%20.%20%5Cfrac%7B1%7D%7Bx%20%2B%2010%7D%20" id="

bezimeni [28]

Hi, I'd be glad to help you with this equation.

Your answer is (5/ x + 3)

Hope this helps.
Have a great day!

8 0

4 years ago

3. Rectangle ABCD is shown on the coordinate grid below.

VMariaS [17]

Answer:

A. 8 units

Step-by-step explanation:

Coordinates of A = (-2, -2)

Coordinates of C = (5, 2)

Use distance formula, $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$ to calculate the length of diagonal $\overline{AC}$ .

Let,

$A(-2, -2) = (x_1, y_1)$

$C(5, 2) = (x_2, y_2)$

$d = \sqrt{(5 -(-2))^2 + (2 -(-2))^2}$

$d = \sqrt{(7)^2 + (4)^2}$

$d = \sqrt{49 + 16} = \sqrt{65}$

$d = 8.1$ (nearest tenth)

Therefore, the closest to the length of diagonal $\overline{AC} = 8 units$

4 0

3 years ago