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OleMash [197]
2 years ago
6

Congratulations I was forced to do this so I could see the question.?

Mathematics
1 answer:
disa [49]2 years ago
4 0
Nobody can provide an answer to you if you do not ask a question that has a viable answer?
You might be interested in
Need help on this please
VladimirAG [237]

Area of the sector = 90/360 ×πr^2

=1/4 ×3.142×6×6

=1/4×113.112

=28.278kilometers square

Approximately 28kilometers square

4 0
3 years ago
Solve x^2 + 6x = 7 by completing the square. Which is the solution set of the equation? {–7, 1}
marishachu [46]

Add 9 to both sides to form a perfect square trinomial:

x² + 6x = 7

x² + 6x + 9 = 16

x² + 2•x•3 + 3² = 16

(x + 3)² = 16

(recall that (a + b)² = a² + 2ab + b²)

Now solve for x. Taking square roots on both sides, we get

x + 3 = ± √16

x + 3 = ± 4

x = -3 ± 4

so the two solutions are x = -7 and x = 1.

3 0
2 years ago
Evaluate the following expression exactly: cosine of 120°<br><img src="https://tex.z-dn.net/?f=cos%28120%29" id="TexFormula1" ti
scoray [572]

Answer:

cos(120°) =  -1/2° or 0.5°

Step-by-step explanation:


3 0
4 years ago
Read 2 more answers
2/9 in decimal and percent form?​
ipn [44]

Answer:

2.9% = 0.029 in decimal form. Percent means 'per 100'. So, 2.9% means 2.9 per 100 or simply 2.9/100. If you divide 2.9 by 100, you'll get 0.029

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Find the distance between (-5,6)and (3,2).
skad [1K]

Answer:

\displaystyle d = 4\sqrt{5}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, 6) → x₁ = -5, y₁ = 6

Point (3, 2) → x₂ = 3, y₂ = 2

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formulas]:                                                     \displaystyle d = \sqrt{(3+5)^2+(2-6)^2}
  2. [Distance] [√Radical] (Parenthesis) Add/Subtract:                                       \displaystyle d = \sqrt{(8)^2+(-4)^2}
  3. [Distance] [√Radical] Evaluate exponents:                                                    \displaystyle d = \sqrt{64+16}
  4. [Distance] [√Radical] Add:                                                                             \displaystyle d = \sqrt{80}
  5. [Distance] [√Radical] Simplify:                                                                         \displaystyle d = 4\sqrt{5}
6 0
3 years ago
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