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3 years ago

Please help for brainliest

Mathematics

1 answer:

Serga [27]3 years ago

3 0

Answer:

841.6 ft

Step-by-step explanation:

Solve this using the quadratic formula.

y=-16x^2+212x+139 becomes -16x^2 + 212x + 139. The x-value of the axis of symmetry is

-212

x = ----------- = 6.625 (This time measurement is in seconds.)

2(-16)

The maximum height reached by the rocket is the y value when x = 6.625 and is y(6.625) = 841.6 ft

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Callie has a new kitten. The kitten weighs 3 pounds less than half the weight of Callie’s cat. Together, the cat and the kitten

scoundrel [369]

A) K=1/2C-3
K+C=18

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7 0

3 years ago

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Cows and horses cost $250 each and sheep and goats each cost $200 at the county fair. Chickens sell for $50. How much could McDo

IgorC [24]

Answer:

the total amount of animals in McDonald's farm is missing, so I looked for a similar question and found the attached image:

McDonald can earn:

15 cows x $250 = $3,750

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3 years ago

Solve the equation log^7b>2

ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is $(\log b)^{7} > 2$

⇒ $\log b > 2^{\frac{1}{7} }$

We are taking the base of the log here is 10.

So, $10^{(\log b)} > 10^{2^{\frac{1}{7} } }$ {Since $10^{\log x} =x$ and $e^{\ln x} = x$ }

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3 0

3 years ago

Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow

prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

$CI=\hat{Y}\pm t_{Critical}\times S_{e}$

Where,

$\hat{Y}=$ predicted value of lead content when traffic flow is 15.

$\to df=n-1=8-1=7$

$95\% \ CI\ is\ (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\$

$=\frac{1059.8}{2}\\\\=529.9$

Calculating thet-critical value $t_{ \{\frac{\alpha}{2},\ df \}}=-2.365$

The lower predicted value $=529.9-2.365(Se)$

$463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076$

When $99\%$ of CI use as the expected lead content: $\to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)$

8 0

3 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago