Answer:
![A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-6%5C%5C8%265%5C%5C19%26-10%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given
![A =\left[\begin{array}{cc}2&-2\\3&4\\4&-3\end{array}\right]](https://tex.z-dn.net/?f=A%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D2%26-2%5C%5C3%264%5C%5C4%26-3%5Cend%7Barray%7D%5Cright%5D)
![B = \left[\begin{array}{cc}4&-1\\-1&2\end{array}\right]](https://tex.z-dn.net/?f=B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcc%7D4%26-1%5C%5C-1%262%5Cend%7Barray%7D%5Cright%5D)
Required

To do this, we simply multiply the rows of A by the column of B;
So, we have:
![A * B = \left[\begin{array}{ccc}2*4 + -2*-1&2*-1+-2*2\\3*4+4*-1&3*-1+4*2\\4*4-3*-1&4*-1-3*2\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D2%2A4%20%2B%20-2%2A-1%262%2A-1%2B-2%2A2%5C%5C3%2A4%2B4%2A-1%263%2A-1%2B4%2A2%5C%5C4%2A4-3%2A-1%264%2A-1-3%2A2%5Cend%7Barray%7D%5Cright%5D)
![A * B = \left[\begin{array}{ccc}10&-6\\8&5\\19&-10\end{array}\right]](https://tex.z-dn.net/?f=A%20%2A%20B%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D10%26-6%5C%5C8%265%5C%5C19%26-10%5Cend%7Barray%7D%5Cright%5D)
Peter piper picked a pepper
Answer:
The Height of the cliff is 41.5 meters tall.
Option B. 41.5 meters.
Step-by-step explanation:
Given:
AB = 85 meter
Angle of elevation ∠ C= 26°
To Find:
Cliff height = AB = ?
Solution:
In right angle Triangle ABC by tangent Identity we have

Substituting the given values we get


The Height of the cliff is 41.5 meters tall.
Answer:
1)x=21.33
2)Height of tree is 20 m
Step-by-step explanation:
Question 1
ΔABC ≈ΔADE
Property of similar triangles :Corresponding sides of similar triangles are all in the same proportion
So,
Question 2: Find the height of tree
ΔDEF ≈ΔDHI
Property of similar triangles :Corresponding sides of similar triangles are all in the same proportion
So,
Hence The height of tree is 30 m
The dog house consists of two geometric objects, triangular prism and rectangular prism.
First, find the surface area of triangular prism
The triangular prism consists of
base of triangle (b) = 3 ft
height of triangle (h) = 2.5 ft
height of prism or length of rectangle (l) = 4 ft
side of triangle or width of rectangle (w) = 2.5 ft
Now, calculate the area
area of tp = area of two triangle + area of 2 rectangle
area of tp = (2 × 1/2 × b × h) + (2 × l × w)
area of tp = (2 × 1/2 × 3 × 2) + (2 × 4 × 2.5)
area of tp = 6 + 20
area of tp = 26 ft²
Second, find the surface area of rectangular prism
The rectangular prisms consists of
length (l) = 3 ft
width (w) = 4 ft
height (h) = 2 ft
Now, calculate the area
area of rp = area of back and front rectangle + area of left and right rectangle
area of rp = (2 × l × h) + (2 × w × h)
area of rp = (2 × 3 × 2) + (2 × 4 × 2)
area of rp = 12 + 16
area of rp = 28 ft²
Third, add both of the area
area = area of tp + area of rp
area = 26 + 28
area = 54 ft²
The area of the dog house is 54 ft²