The perimeter, by definition, is the outside measure of that figure. MN and LM are the same length and LK and NK are the same length....we just need to find the lengths! Use the distance formula to find the distance between the 2 points:
![\sqrt{( x_{2} - x_{1} ) ^{2} +( y_{2}- y_{1} ) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%28%20x_%7B2%7D%20-%20x_%7B1%7D%20%29%20%5E%7B2%7D%20%2B%28%20y_%7B2%7D-%20y_%7B1%7D%20%29%20%5E%7B2%7D%20%20%7D%20)
For the segment MN, use the coordinates of M as your x1, y1, and use the coordinates of N for x2, y2:
![\sqrt{(3-2) ^{2}+(4-3) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%283-2%29%20%5E%7B2%7D%2B%284-3%29%20%5E%7B2%7D%20%20%7D%20)
which simplifies to
![\sqrt{(1 )^{2}+(1) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%281%20%29%5E%7B2%7D%2B%281%29%20%5E%7B2%7D%20%20%7D%20)
which is
![\sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20)
So that is the length of both MN and LM. So far our perimeter is
![\sqrt{2} + \sqrt{2}=2 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B2%7D%20%2B%20%5Csqrt%7B2%7D%3D2%20%5Csqrt%7B2%7D%20%20)
Now let's use the same formula to find out the length of one of the longer segments:
![\sqrt{(5-3) ^{2} +(3-2) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%285-3%29%20%5E%7B2%7D%20%2B%283-2%29%20%5E%7B2%7D%20%7D%20)
which simplifies down to
![\sqrt{(2) ^{2} +(1) ^{2} }](https://tex.z-dn.net/?f=%20%5Csqrt%7B%282%29%20%5E%7B2%7D%20%2B%281%29%20%5E%7B2%7D%20%7D%20)
which is of course
![\sqrt{5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20)
Since we have 2 of those lengths,
![\sqrt{5} + \sqrt{5}=2 \sqrt{5}](https://tex.z-dn.net/?f=%20%5Csqrt%7B5%7D%20%2B%20%5Csqrt%7B5%7D%3D2%20%5Csqrt%7B5%7D%20%20)
So our perimeter is, in the end,
![2 \sqrt{2}+2 \sqrt{5}](https://tex.z-dn.net/?f=2%20%5Csqrt%7B2%7D%2B2%20%5Csqrt%7B5%7D%20%20)
That's the third choice down
Answer:
C
Step-by-step explanation:
The main piece of computer software on which every other piece of software relies is referred to as the "operating system". It is responsible for all the major channels of communication between the software and the hardware.
Answer: x = 4
Step-by-step explanation:
We'll call the number "x."
"Twice the difference of a number and 3" means 2(x-3)
is equal to 2: =2
Put them together:
2(x-3) =2
2x - 6 = 2
2x = 8
x = 4
Check:
2(x-3)
Twice the difference of a number and 3 is equal to 2
2(4 - 3) = 2 ?
<h2>2(1) = 2 <u>
Yes</u></h2>
The correct answer is C, if you use the distributive property and multiply all of them by each other you would get x^3+2x^2+3x+6.
Hope this helps :-)