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devlian [24]
3 years ago
5

CAN YOU HELP ME PLEASE I NEED THIS RIGHT NOW I DONT UNDERSTAND

Mathematics
1 answer:
Neporo4naja [7]3 years ago
4 0

Answer:

divide the smaller number by the larger number

Step-by-step explanation:

54.8% or 55%

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7.55 rounded to the first decimal place
lina2011 [118]
7.6
usually, if it's 5 or higher, you round up
6 0
3 years ago
Ben's Sports sells golf tees from a barrel by the scoop. The golf tees come in 5 bright colors mixed in the barrel. To determine
My name is Ann [436]
It’s C i did it on edgunity and i got the answer correct!!
4 0
3 years ago
If rs 500 amounts to Rs 725 at 9% simple interest in sometime ,what will Rs 600amount to at 11% in same time?
Y_Kistochka [10]

Answer:

Rs\ 930

Step-by-step explanation:

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

step 1

Find the number of time periods t

in this problem we have

t=?\ years\\ P=Rs\ 500\\ A=Rs\ 725\\r=0.09

substitute in the formula above  and solve for t

725=500(1+0.09t)

t=[(725/500)-1]/0.09

t=5\ years

step 2

what will Rs 600 amount to at 11% in same time?

we have

t=5\ years\\ P=Rs\ 600\\ A=?\\r=0.11

substitute in the formula

A=600(1+0.11*5)

A=600(1.55)

A=Rs\ 930

6 0
3 years ago
Can someone please help me with this question??
liraira [26]

Answer:

The probability that a randomly chosen child in 11th grade and play tennis is 9.6% ⇒ D

Step-by-step explanation:

  • P(A) and P(B) =  P(A) . P(B)
  • P(A) or P(B) = P(A) + P(B)

The table represents the percentage of the students in each sport

→ The rows represent the grades level, the columns represent the sports

∵ The percentage of students in grade 11 = 40%

∴ The probability of choosing a child in grade 11th = \frac{40}{100} = 0.40

∵ The percentage of students who playing tennis = 24%

∴ The probability of choosing a child who playing tennis = \frac{24}{100} = 0.24

→ We need to find the probability of a randomly chosen child in

   11th grade and playing tennis

∵ The probability of A and B is P(A) . P(B), where P(A) is the probability of

   choosing a child in 11th grade and P(B) is the probability of choosing

   a child playing tennis

∵ P(A) = 0.40 and P(B) = 0.24

∴ P(A) and P(B) = 0.40 × 0.24

∴ P(A) and P(B) = 0.096

→ Change it to a percentage by multiplying it by 100

∴ P(A) and P(B) = 0.096 × 100%

∴ P(A) and P(B) = 9.6%

∴ The probability that a randomly chosen child in 11th grade and

   play tennis is 9.6%

4 0
3 years ago
Solve for y<br> 40 = 4y - 16
aliya0001 [1]

Answer:

y = 14

Step-by-step explanation:

40 = 4y - 16

40 + 16 = 4y - 16 + 16

56 = 4y

56/4 = 4y/4

y = 14

5 0
3 years ago
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