Answer:
Gold
Step-by-step explanation:
<em>Casandra finds a treasure chest packed with metallic coins. The chest has a volume of 0.25 cubic meters. The coins have a combined mass of 4825 kg. Hoping to find gold, she calculates the density to determine the metal of the coins.</em>
<em>What kind of metal are the coins made of?</em>
<em>Bronze (8700 kg per cubic meter)</em>
<em>Silver (10500 kg per cubic meter)</em>
<em>Lead (11300 kg per cubic meter)</em>
<em>Gold (19300 kg per cubic meter)</em>
<em />
Density is mass per volume:
D = M / V
D = (4825 kg) / (0.25 m³)
D = 19,300 kg/m³
The coins must be made of gold.
The correct answer is B.
16-9=7
So, 7+9=16.
If we add to 9 only 1 (out of those 7) we have then 10, remaining 6.
9+1=10
Now, if to 10 we add the remaining 6 we will have the final 16.
10+6=16
16-9=7 <=> 9+7=16 <=> (9+1)+6=16
B, there is no angles so it has to be SSS
Answer: 45 dollars and it was a distance of 5 kilometers
Step-by-step explanation: What i did was start with 30, then keep adding 3 till i got the a multiple of 5.
30 + 3 = 33
33 + 3 = 36
36 + 3 = 39
39 + 3 = 42
42 + 3 = 45
So already i know that it is 5 kilometers, because i added 3 to 30 five times.
No i will do that with the second company
20 + 5 = 25
25 + 5 = 30
30 + 5 = 35
35 + 5 = 40
40 + 5 = 45
That is also 5 kilometers, because i added 5 to 20 five times. I also know they are the same price, because they both added to 45 dollars.
Thats how i solved it.
I really hope that helps!
Answer:
f'(x) > 0 on 
and f'(x)<0 on
Step-by-step explanation:
1) To find and interval where any given function is increasing, the first derivative of its function must be greater than zero:
To find its decreasing interval :
2) Then let's find the critical point of this function:
![f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0](https://tex.z-dn.net/?f=f%27%28x%29%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7D%20x%7D%5B6-2%5E%7B2x%7D%5D%3D%5Cfrac%7B%5Cmathrm%7Bd%7D%20%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B6%5D-%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2%5E%7B2x%7D%5D%3D0-%5Bln%282%29%2A2%5E%7B2x%7D%2A%5Cfrac%7B%5Cmathrm%7Bd%7D%7D%7B%5Cmathrm%7Bd%7Dx%7D%5B2x%5D%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%3D-ln2%2A2%5E%7B2x%2B1%5CRightarrow%20%7Df%27%28x%29%3D-ln%282%29%2A2%5E%7B2x%7D%2A2%5C%5C-ln%282%29%2A2%5E%7B2x%2B1%7D%3D-2x%5E%7B2x%7D%28ln%28x%29%2B1%29%3D0)
2.2 Solving for x this equation, this will lead us to one critical point since x' is not defined for Real set, and x''
≈0.37 for e≈2.72
3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.
