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GuDViN [60]
2 years ago
11

Please help I domt understand​

Mathematics
1 answer:
Varvara68 [4.7K]2 years ago
6 0
Standard form of an equation is Ax + By = C
So here, y = 2/5 * x - 3
y = (2x - 15) / 5
5y = 2x - 15
2x - 5y = 15
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Line segment TV is a midsegment of ∆QRS. What is the value of n in the triangle pictured?
Elis [28]

Answer:

D. 3.2

Step-by-step explanation:

Mid-segment Theorem of a triangle states that the Mid-segment in a triangle is half of the third side of the triangle.

Based on this theorem, we have: TV = ½(RS)

TV = 3n - 2

RS = n + 12

Substitute

3n - 2 = ½(n + 12)

Multiply both sides by 2

2(3n - 2) = (n + 12)

6n - 4 = n + 12

Collect like terms

6n - n = 4 + 12

5n = 16

Divide both sides by 5

5n/5 = 16/5

n = 3.2

4 0
3 years ago
6 = a/4 + 2<br><br> What’s the answer for the variable a?
Vikki [24]

Answer:

a = 16

Step-by-step explanation:

6 = a/4 + 2

4 = a/4            Subtract 2 from both sides

16 = a                 Multiply 4 to both sides

7 0
3 years ago
Read 2 more answers
What is the area of a regular octagon with a side length of 4.6 meters and a length from the center to a vertex of 6 meters? HEL
Shtirlitz [24]

<span>What is the area of a regular octagon with a side length of 4.6 meters and a length from the center to a vertex of 6 meters? 

Good Morning
 
The Correct Answer is c) 101.2

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6 0
3 years ago
I don't get this I need help?
Aleks04 [339]

Answer: 4r^2

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
In a 33' by 69.7' room, what is the diagonal length from corner to corner along the floor?
KonstantinChe [14]

Answer:

77.12 feets

Step-by-step explanation:

In a 33' by 69.7' room, what is the diagonal length from corner to corner along the floor?

Step one:

given data

Length of the room= 33 feets

width of the room = 69.7 feets

Required

The diagonal of the room

Step two:

from Pythagoras theorem

z^2= x^2+y^2

substitute

z^2= 33^2+ 69.7^2

z^2=1089+4858.09

z^2=5947.09

z=√5947.09

z=77.12 feets

8 0
3 years ago
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